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OLEGan [10]
3 years ago
12

I need help.. >w<

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

C) 30 + 6 + 0.9 + 0.05

Step-by-step explanation:

30. 0.9. 36

+6. +0.05. +00.95

---------. -------------. ---------------

36. 0.95. 36.95

----------. --------------. --------------

36+0.95=36.95

ruslelena [56]3 years ago
3 0

Answer:

O C)30+6+0.6+0.05 hope this helps

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Please help please please help me please help please please
Leona [35]

Answer:

y - 6 = -3 ( x - 7)

Step-by-step explanation:

Use one of the points.

m is the slope

4 0
3 years ago
If the expression x^{-\frac{3}{2}}y\sqrt{36xy^2}x − 2 3 ​ y 36xy 2 ​ is written in the form ax^by^cax b y c , then what is the p
Mekhanik [1.2K]

Answer:

-12

Step-by-step explanation:

The given expression is

x^{-\frac{3}{2}}y\sqrt{36xy^2}

We have to rewrite the given function in the form of  

ax^{b}y^c          ....(i)

then we have to find the product of a,b and c.

The given expression can be rewritten as

x^{-\frac{3}{2}}y\sqrt{36}\sqrt{x}\sqrt{y^2}

Using properties of exponents we get

x^{-\frac{3}{2}}y6x^{\frac{1}{2}}y       [\because \sqrt[n]{a}=a^{\frac{1}{n}}]

6x^{-\frac{3}{2}+\frac{1}{2}}y^{1+1}      [\because a^ma^n=a^{m+n}]

6x^{-1}y^{2}      ...(ii)

On comparing (i) and (ii), we get

a=6,b=-1,c=2

Product of a,b and c is

abc=(6)(-1)(2)=-12

Therefore, the product of a,b, and c is -12.

7 0
4 years ago
The length of a rectangle is 5 m greater than the width. The perimeter is 150 m. find the width
Elza [17]

P = perimeter

Perimeter of a rectangle = l + l + w + w

or  P = 2l + 2w

You know:

P = 150 m

l = w + 5     [length is 5 m greater than the width]

P = 2l + 2w        Plug in what you know

150 = 2(w + 5) + 2w     Simplify, distribute/multiply 2 into (w + 5)

150 = 2w + 10 + 2w

150 = 4w + 10     Subtract 10 to both sides of the equation

140 = 4w       Divide 4 on both sides

35 = w

PROOF               l = w + 5 --->  l = 40

P = 2l + 2w

150 = 2(40) + 2(35)

150 = 80 + 70

150 = 150

4 0
4 years ago
What is the answer to m-4=2m
Levart [38]
Subtract mm from both sides -4=2m-m−4=2m−m 2 Simplify 2m-m2m−m to mm -4=m−4=m 3 Switch sides m=-4m=−4
5 0
4 years ago
Read 2 more answers
A solid oblique pyramid has a regular pentagonal base. The base has an edge length of 2.16 ft and an area of 8 ft2. Angle ACB me
choli [55]
Volume of the pyramid:
V = 1/3 · B · h
B = 8 ft²
tan 30° = height / 7√3
1/√3 = height / 7√3
height = 7 ft
V =  1/3 · 8 · 7 = 18.67 ft³ ≈ 19 ft³
Answer : D ) 19 ft³
3 0
4 years ago
Read 2 more answers
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