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2 years ago

Answer this answer this answer this

Mathematics

2 answers:

Elodia [21]2 years ago

8 0

Answer:

5x+3×2x

8x-1×6x+5x+3×2x

write this and solve this if i tell u all u can't learn urself thank u

avanturin [10]2 years ago

5 0

Answer:

If we are trying to find the area if the blue rectangle, the answer is 38x²-12x.

Step-by-step explanation:

Area of blue + white: (8x-1) × (6x) = 48x²-6x

Area of white: (5x+3) × (2x) = 10x²+6x

Area of just blue: (48x²-6x) - (10x²+6x) = 38x² - 12x

You might be interested in

use the distributive property to remove parentheses. Simplify your answer as much as possible. 1/2(4y+7)

Anna007 [38]

1/2(4y+7)

Use the distributive property. a(b+c)= ab+ac

1/2*4y= 2y

1/2*7= 3.5

2y+3.5 <---- simplified expression

I hope this helps!
~kaikers

7 0

3 years ago

Read 2 more answers

A boy has only dimes and quarters in his piggy bank. if he has 70 coins worth 12 dollars and 40 cents altogether, how many quart

dlinn [17]

Let us bear in mind the equivalent value of these coins:

One dime = $0.10

One quarter = $0.25

Let x = number of dimes

y = number of quarters

Since the boy has 70 coins in total, we can say that:

x + y = 70 (can be written as x = 70 – y)

Since the boy has a total of $12.40, we can say that:

0.10x + 0.25y = 12.40

To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y)

0.10(70 – y) + 0.25y = 12.40

7 – 0.10y + 0.25y = 12.40

0.15y = 5.40

y = 36

X = 70 – 36

X = 34

Therefore, the boys has 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.

34 dimes = $3.40

36 dimes = $9.00

Total $12.40

7 0

3 years ago

Read 2 more answers

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x$

$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

$\implies \cos^2 (6x)=1- \sin^2 (6x)$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

Expand:

$\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

$\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x$

$\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$

$\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}$

$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

Simplify:

$\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}$

$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

brainly.com/question/27805589

brainly.com/question/28155016

3 0

2 years ago

The sum of the first five terms of an arithmetic series is 25, and the first term is 2. Find the constant difference.

aivan3 [116]

Step-by-step explanation:

if you calculate both of you should ask her

5 0

3 years ago

which is a shrink of an exponential growth function? a. f(x) = 1/3(3)^x b. f(x) = 3(3)^x c. f(x) = 1/3(1/3)^x d. f(x) = 3(1/3)^x

Gnesinka [82]

Answer: option a.

$f(x)=\frac{1}{3} (3)^x$

Explanation:

A shrink of a function is a shrink on the vertical direction. It means that for a certain value of x, the new function will have a lower value, in the intervals where the function is positive, or a higher value, in those intervals where the function is negative. This is, the image of the new function is shortened in the vertical direction.

That is the reason behind the rule:

given f(x), the graph of the function a×f(x), when a > 1, represents a vertical stretch of f(x),

given f(x), the graph of the function a×f(x), when a < 1, represents a vertical shrink of f(x).

So, we just must apply the rule: to find a shrink of an exponential growth function, multiply the original function by a scale factor less than 1.

Since it is a shrink of an exponential growth function, the base must be greater than 1. Among the options, the functions that meet that conditon are a and b:

$a. f(x)=\frac{1}{3} (3)^x \\ \\ b.f(x) = 3(3)^x$

Now, following the rule it is the function with the fraction (1/3) in front of the exponential part which represents a shrink of an exponential function.

8 0

3 years ago

Read 2 more answers