1) 
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
        
             
        
        
        
B because for it to be a function one X value cant have more than one Y value and B is the only one that follows the rule
        
                    
             
        
        
        
Answer:
The perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.
Step-by-step explanation:
Given : A quarter of a circle with radius labeled 2 in.
Quarter of circle means fourth part of a circle  (as shown in image by shaded part).
 We have to find the perimeter of this shaded quarter of circle.
Perimeter is the sum of the dimension of the given figure.
Perimeter of circle is 
Since, we are given Quarter circle so its perimeter 
Perimeter of given figure = 
Perimeter of given figure = 
Thus, the perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.
 
        
                    
             
        
        
        
When will factor it we will get the factors 2x(x^2+2x+4) so option c is correct.