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V125BC [204]
2 years ago
7

3+1-4+7=? I need help with this

Mathematics
2 answers:
vovikov84 [41]2 years ago
5 0

Answer:

Step-by-step explanation:

first <em>step:    </em>3 + 1 =  4

<em>second step:  </em>4 - 4 = 0

<em>third step:</em>   0 + 7 =<u> 7 </u>  (the answer is 7 )

inysia [295]2 years ago
4 0
The answer is 7, 3 plus 1 equals 4 minus four equals zero plus 7= 7
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78/14 Between which two consecutive whole numbers does this value lie? Enter your numbers in the box
Zigmanuir [339]

Given number is 78/14.

We have to find two whole numbers between which given number 78/14 lies.

Let's convert that into mixed fraction.

To do that we divide 78 by 14 to find the quotient.

We see that 14 goes 5 times into 78 and leaves remainder of 8.

So we can rewrite 78/14 as 5\frac{8}{14}.

5\frac{8}{14} means little more than 5 but less than 6.

So required two whole numbers are 5 and 6.



5 0
3 years ago
Most brainiest for correct answer! :)
nexus9112 [7]

Answer:

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3 0
3 years ago
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If you roll two four-sided dice (numbered 1, 2, 3, and 4), what is the probability that the sum of the dice is 3?
Elan Coil [88]

Answer:

The probability that the sum of the dice is 3, is 3/16.

Step-by-step explanation:

It is given that two four-sided dice are rolled.

Total number of sides of each dice = 4

Possible values for each dice = 1,2,3,4

If two four-sided dice are rolled, then the total possible outcomes are

A=\{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),\\(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)\}

Total number of possible outcomes = 16

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\text{Favorable outcomes}=\{(1,1),(1,2),(2,1)\}

Total number of favorable outcomes = 3

The probability that the sum of the dice is 3.

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Therefore the probability that the sum of the dice is 3, is 3/16.

8 0
4 years ago
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Answer:

C.(10x^2-4) - (7x^2+3)

In option C,

(10x^2-4) - (7x^2+3) = 10x^2 - 4 - 7x^2 - 3 = 3x^2 - 7

⇒ Option C is correct

6 0
3 years ago
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IceJOKER [234]

Answer: (0, 0)

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go 3 units down

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4 0
2 years ago
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