Answer:
5.25 times
Step-by-step explanation:
Beverage A and Beverage B are sold in identical cans.
From the above question
Beverage A is 4% sugar.
The portion of Beverage B that is sugar is 0.21.
Converting Portion of sugar in Beverage B to percentage we have :
0.21 × 100
= 21%
How many times more sugar is in Beverage B than Beverage A?
This is calculated as:
% Beverage B/% Beverage A
= 21%/4%
= 5.25
Hence Beverage B has 5.25 times more sugar than Beverage A.
It equals 3600 combinations
4(equals the types of cones/cup) x 3(the measures of each one) x 20 (ice cream flavors) x 15 (toppings) += 3600 combinations
If there is a picture i could tell you
Answer:
No, the Roger’s claim is not correct.
Step-by-step explanation:
We are given that Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and the median.
This statement by Roger is incorrect because the median is unaffected by the outlier value and only the mean value gets affected by the outlier value.
As the median represents the middlemost value of our dataset, so any value which is an outlier will be either at the start or at the end will not the median value. So, the median will not likely change when an outlier is added to a small data set.
Now, the mean is the average of all the data set values, that is the sum of all the observations divided by the number of observations. The mean will get affected by the outlier value because it take into account each and every value of the data set.
Hence, the mean will likely to change greatly when an outlier is added to a small data set.
Answer:
Step-by-step explanation:
The proportion that Alan solved was
x/200 = 8/25
His working as shown was
(8)(x) = (25) (200)
8x = 5000
He divided both sides of the equation by 8. It became
8x/8 = 5000/8
x = 625
The correct steps are
25x = 200 × 8 = 1600
Dividing both sides of the equation by 25, it becomes
x = 1600/25
x = 64
Alan's error were:
1) He got the wrong product when he multiplied 25 by 200.
2)He got the wrong quotient when he divided 5,000 by 8.
