All categories

2 years ago

What is the missing number. Explain how you determined your answer. 5–8–14–26–50–?—194

Mathematics

1 answer:

katrin2010 [14]2 years ago

4 0

Answer:

5-8 is +3

8-14 is +3*2

14-26 is 3*4

26-50 is 3*8

which means 50 to the next number is 3*16, which is 48

48+50 is 98

Step-by-step explanation:

You might be interested in

**Jane found money in her pocket. She went to a convenience store and spent 1/4 of her money on chocolate milk, 3/5 of her money

valentina_108 [34]

Answer:

3/20

Step-by-step explanation:

1/1-1/4-3/5= (money spent)

1×4×5/(1×4×5)-1×1×5/(1×4×5)-3×1×4/(1×4×5)

20/20-5/20-12/20

(20-5-12)/20=3/20

8 0

2 years ago

Read 2 more answers

Y=arccos(1/x) Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago

A dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 pe

puteri [66]

Answer:

The correct option is B. 23%

Step-by-step explanation:

Let the event that patient brushes his teeth at least twice a day is denoted by A

So, P(A) = 0.83

Let the event that patient flosses daily is denoted by B

So, P(B) = 0.47

Now, it is given that 19 percent patients brush at least twice a day and floss daily.

⇒ P(A and B) = 0.19

Now, we need to find conditional probability of occurring event B given A has occurred.

$\implies P(B|A) =\frac{P(A\: and\: B)}{P(A)}\\\\\implies P(B|A) = \frac{0.19}{0.83}\\\\\implies P(B|A) = 0.2289\approx 0.23$

Hence, Nearest required percentage = 23%

Therefore, The correct option is B. 23%

4 0

2 years ago

Read 2 more answers

One-hundred people were surveyed to find if they owned a cat

r-ruslan [8.4K]

Answer:

1. I dont know what format they want you to write it in but its 27/100 which is 0.27 as a decimal and 27% as a percent

2. it'll be 11/100 which is 0.11 as a decimal and 11% as a percent

Step-by-step explanation:

Since adding up all the people with cats, dogs or both is 73, and theres 100 people surveyed, that means 100-73=27 so 27 people dont have a cat or dog. Therefore its 27/100 which is 0.27 as a decimal and 27% as a percent

For number 2, because 11 people have both a dog and cat I believe itll be 11/100 which is 0.11 as a decimal and 11% as a percent

4 0

2 years ago

What's the answer to: 2/3x -4=-2

olga2289 [7]

2/3x -4=-2
-------------------
Add 4 to each side
2/3x-4+4=-2+4
2/3x = 2
-----------------------------
Multiply each side by 3/2
(3/2) * (2/3x) = (3/2) * (2)
x = 3

8 0

3 years ago