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Mariana [72]
2 years ago
15

Ed has 30 sweets the ratio of red to yellow sweets is 2:3 how many red sweets does ed have

Mathematics
1 answer:
laila [671]2 years ago
5 0

<em>Refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>attachments</em><em>!</em><em>!</em><em>~</em>

\rule{300pt}{3pt}

Number of red sweets = 12

Number of yellow sweets = 18

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Mr Thompson please help with my new HW
sesenic [268]

Answers:

  1. C) x = plus/minus 11
  2. B) No real solutions
  3. C) Two solutions
  4. A) One solution
  5. The value <u>  18  </u> goes in the first blank. The value <u>  17  </u> goes in the second blank.

========================================================

Explanations:

  1. Note how (11)^2 = (11)*(11) = 121 and also (-11)^2 = (-11)*(-11) = 121. The two negatives multiply to a positive. So that's why the solution is x = plus/minus 11. The plus minus breaks down into the two equations x = 11 or x = -11.
  2. There are no real solutions here because the left hand side can never be negative, no matter what real number you pick for x. As mentioned in problem 1, squaring -11 leads to a positive number 121. The same idea applies here as well.
  3. The two solutions are x = 0 and x = -2. We set each factor equal to zero through the zero product property. Then we solve each equation for x. The x+2 = 0 leads to x = -2.
  4. We use the zero product property here as well. We have a repeated factor, so we're only solving one equation and that is x-3 = 0 which leads to x = 3. The only root is x = 3.
  5. Apply the FOIL rule on (x+1)(x+17) to end up with x^2+17x+1x+17 which simplifies fully to x^2+18x+17. The middle x coefficient is 18, while the constant term is 17.
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3 years ago
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svlad2 [7]
Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer

Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
-2x - 6. -2x -6
0 = x^2 + 3x. Factor
0 = x (x + 3)
Solve: x = 0. x + 3 = 0. ——> x = -3. Substitute into one original equation to get y value for
y = 2x + 6.
y = 2(0) + 6. y = 2(-3) + 6
y = 6. y = -6 + 6 —-> y = 0
(0 , 6) And. (-3 , 0)

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3 years ago
If 12 and 20 each divide K without a remainder, what is the value of K?
Juli2301 [7.4K]

Factors of 12 : 1, 2, 3, 4, 6, 12

Factors of 20: 1, 2, 4, 5, 10, 20

In both lists of factors, 4 is in common. Therefore, the value of K is 4 because it can divide into both 12 and 20 without a remainder. 2 is also another possible value of K.

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The correct answer is A because the 4 in the X value repeats two time and on the other ones doesn't
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