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3 years ago

Thecircferenceof the wheel of a bus is 2.8m .How many revolution does it make to cover 3.5km?

Mathematics

1 answer:

stepan [7]3 years ago

7 0

Answer:

3.5 X 1000 = 3500m

3500/2.8 = 1250

1250 revolutions

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Answer:

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Step-by-step explanation:

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3 years ago

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sergij07 [2.7K]

Answer:

48 length units

Step-by-step explanation:

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Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago

you are on a 750 mile trip by car . ur car used seven gallons of gas to travel the first 210 miles of the trip. how much more ga

stepan [7]

Answer:

A total of 18 gallons of more gas

Step-by-step explanation:

7 gallons = 210 miles

750-210= 540

210*2 =420 miles 7*2=14 gallons

210/2= 105 7/2=3.5 gallons

525 miles 17.5 miles

210/14= 15 7/14=.5 gallons

540 miles 18 gallons

6 0

3 years ago

Thecircferenceof the wheel of a bus is 2.8m .How many revolution does it make to cover 3.5km?​

Thecircferenceof the wheel of a bus is 2.8m .How many revolution does it make to cover 3.5km?