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2 years ago

What is the equation of a line that passes through the points (0,0) and (5,2)

Mathematics

1 answer:

mafiozo [28]2 years ago

5 0

Answer:

y = 2/5x

Step-by-step explanation:

in order to get the y-intercept (b) , the value of x has to be zero. we already have the y-intercept which is zero. so far, the equation looks like this:

y = mx + 0

in order to find the slope, we'll do y2-y1 / x2 - x1:

2-0

5-0

m is 2/5, so the answer is:

y = 2/5x

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belka [17]

6/10 rounding to the nearest half would be 1, not 0.

Reason for this: Here is a number line to help you!

|----|----|

Left line = 0

Middle line = 1/2

Right line = 1

Here is another rule!

0/10, 1/10, 2/10, 3/10, 4/10 = rounded to the nearest half would be 0

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So 6/10 rounded to the nearest half is 1.

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3 years ago

Graph the line passing through the given point and having the given slope (0,3), m=4

andriy [413]

Hint :-

To find out the equation of the line we can use the point slope form of the line which is $y - y_1 = m(x-x_1)$

Solution :-

The given point to us is , $(0,3)$ and the slope of the line is 4 . On using the point slope form , we have ,

$\implies y - y_1= m(x-x_1) \\\\\implies y-3 = 4(x-0) \\\\\implies y -3 = 4x \\\\\implies \boxed{ 4x - y + 3 =0}$

Hence the equation is 4x - y + 3 = 0 

( for graph , see attachment ) .

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