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Maru [420]
2 years ago
11

PLEASE HELP NOW Is this proportional?

Mathematics
2 answers:
Valentin [98]2 years ago
5 0

Answer:

yes they are proportional

Step-by-step explanation:

Nutka1998 [239]2 years ago
5 0

Answer:

they are not in proportion

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option B

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The symmetric distribution have close or approximate values of median and mean. In the given scenario mean is 48.5 and median is 33. We can see that the both values significantly differs. Also, given mean is greater than median(48.5>33) . Thus, the distribution is positively skewed and not symmetrical.

Hence, the distribution is skewed because mean and median significantly differ from each other.

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If times AB and CB are parallel, then angels c and e are
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because c and g are same and g and e are complementary.

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Use the distributive property to simplify the expression 5(7r+2+4p)
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The weather forecast in a city is that for every week, 3 days are sunny 2 are cloudy, and 2 are rainy. On any chosen day, descri
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3 years ago
From her purchased bags, Rory counted 110 red candies out of 550 total candies. Using a 90% confidence interval for the populati
Svetlanka [38]

Answer:

The Confidence Interval = (0.172, 0.228)

Where:

The lower limit = 0.172

The upper limit = 0.228

Step-by-step explanation:

The formula to be applied or used to solve this question is :

Confidence Interval formula for proportion.

The formula is given as :

p ± z × √[p(1 - p)/n]

n = Total number of red candies = 550 red candles

p = proportion = Number of red candies counted/ Total number of red candies

= 110/550 = 1/5 = 0.2

z = z score for the given confidence interval.

We are given a confidence interval of 90%. Therefore, the z score = 1.6449

Confidence Interval = p ± z × √[p(1 - p)/n]

Confidence Interval = 0.2 ± 1.6449 × √[0.2(1 - 0.2)/550]

= 0.2 ± 1.6449 √0.2 × 0.8/550

= 0.2 ± 1.6449 × 0.0170560573

= 0.2 ± 0.0280555087

Hence, the Confidence Interval = 0.2 ± 0.0280555087

0.2 - 0.0280555087 = 0.1719444913

Approximately = 0.172

0.2 + 0.0280555087 = 0.2280555087

Approximately = 0.228

Therefore, the Confidence Interval = (0.172, 0.228)

Where:

The lower limit = 0.172

The upper limit = 0.228

4 0
3 years ago
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