Answer:
bowl and sometimes if im not tired then i chop up some children
i have a really good recipe if you want me to share it with you
Answer:
1:
p-r/6=-6-(-6)/6=-6+1=<u>-</u><u>5</u>
<u>2</u><u>:</u>
<u>p-</u><u>(</u><u>m-n</u><u>)</u><u>=</u> -1-(-4-4)=-1-(-8)=-1+8=<u>7</u>
3:
(z+y)/2)3=(-5-4)/3=-9/3=<u>-</u><u>3</u>
<u>4</u><u>:</u>
m/6-n=6/6-6=1-6=<u>-</u><u>5</u>
5:
k³-h=3³-(-2)=27+2=<u>2</u><u>9</u>
6:
p-(p-(m-3))=5-(5-(4-3))=5-(5-1)=5-4=<u>1</u>
7:
(k)(k-j)+3=(5)(5-5)+3=5*0+3=<u>3</u>
8.
p²/6-q=6²/6-4=6-4=<u>2</u>
<u>9</u><u>;</u>
zx+3³=6*4+3³=24+27=<u>5</u><u>1</u><u>.</u>
<u>1</u><u>0</u><u>:</u>
<u>y</u><u>+</u><u>z</u><u>-</u><u>(</u><u>y</u><u>-</u><u>x</u><u>)</u><u>=</u>5+4-(5-2)=9-3=<u>6</u>
<u>S</u><u>o</u><u>m</u><u>e</u><u> </u><u>b</u><u>a</u><u>s</u><u>i</u><u>c</u><u> </u><u>r</u><u>u</u><u>l</u><u>e</u><u>s</u><u>:</u>
+. +. +=+
+. * +=+
+. ÷ +=+
+. - +=+
and
+. +. -=add and put sigh of greater one.
-. * +=-sigh
-÷-=+sigh
- - -=add and put - sigh
The answer to this is 7.5.
So if we want to know the least amount, we first want to assume the other two games both had a score of 52, so we can say the last one had the least possible.
So if both got 52, the total points would be 104, for two games of 52 points. Since we want 141 points, we therefore want 37 more points to reach 141.
So the least amount of points a player could've scored in one of the games was 37.
The answer is B I agree with him/her
