For no real solution, you must have b^2 - 4ac of the quadratic formula be less than 0.
a = 1; b = 2; c = C
b^2 - 4ac < 0
2^2 - 4(1)(C) < 0
4 - 4C < 0
-4C < -4
C > 1
The only choice greater than 1 is 3.
Answer: the 4th choice, 3
Here is the equation I did to solve your problem:
For our variable we will use Adult to represent A
:PEMDAS:
6a+3s
6(2)+3(3)
12+9=$21
Therefore they will pay $21, if two adults and three children go to the movies.
Music notes? Blah blah blah blah
4/5. 4/5 is the correct answer
