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elena55 [62]
2 years ago
13

Adult tickets for a movie cost $6 and children’s tickets cost $3. If two adults and three children go to the movies, how much wi

ll they pay?
Use PEMDAS. Please Help.
Mathematics
2 answers:
Phoenix [80]2 years ago
6 0
Here is the equation I did to solve your problem:

For our variable we will use Adult to represent A

:PEMDAS:
6a+3s

6(2)+3(3)

12+9=$21

Therefore they will pay $21, if two adults and three children go to the movies.
klasskru [66]2 years ago
4 0

Answer:

$21

Procedure:

(6) (2) = 12          (3) (3) = 9

Verification

12 / 2 = 6           9 / 3 = 3

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bearhunter [10]

3.36242487588 is the answer


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2 years ago
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there are thirty-three students in the chess club. there are five more boys than girls in the club. write and solve a system of
bixtya [17]
Girls=g
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33=g+(g+5)
33=g+g+5
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3 years ago
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xenn [34]
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Purchased a vase and flowers at her local flower shop. At home, she wants to fill the cylindrical vase and at the
Paraphin [41]

Step-by-step explanation:

We know that

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=> Radius = 2/2

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3 0
2 years ago
I forgot to send this in my last question, Sorry!
pshichka [43]

1. \:  =  > 4( - 7) \\  = 4 \times  - 7 \\  =  - 28

3. \:  =  > 9( - 12) \\  = 9 \times  - 12 \\  =  - 108

4. \:  =  >  - 6( - 8.75) \\  = 6 \times 8.75 \\  = 52.5

5. =  > 27( - 3) \\  = 27 \times  - 3 \\  =  - 81

7. \:  =  >  - 55(0) \\  - 55 \times 0 \\  = 0

8. \:  =  > ( - 7)( - 7.25) \\  = 7 \times 7.25 \\  = 50.75

11. \:  =  > ( - 1) {}^{4}  \\  = 1 {}^{4}  \\  = 1

13. =  > 42 \div ( - 7) \\  =  - (42 \div 7) \\  =  - 6

15. =  >  - 9 \div 3 \\  =  - (9 \div 3) \\  =  - 3

<h2>Solved ✔︎</h2>

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