Ask question

Ask question

All categories

2 years ago

11

Kai had a gross weekly paycheck of $616 last week. Kai worked 6 hours for 4 of the days and 8 hours on 1 day. What is Kai's hour

ly rate of pay? a. $16. 21 b. $19. 25 c. $20. 53 d. $25. 67 Please select the best answer from the choices provided A B C D.

1 answer:

Goryan [66]2 years ago

7 0

Kai's hourly rate of pay is $19.25/hour.

<h2>Given to us</h2>

Kai had a gross weekly paycheck of $616 last week.
Kai worked 6 hours for 4 of the days, and
Kai worked 8 hours in 1 day

<h2>Total work time of Kai</h2><h3>From Statement 2,</h3>

Kai worked 6 hours for 4 of the days, and

$\begin{aligned}Time_2 &= 6\ hours \times 4\ days\\&= 6 \times 4\\&= 24\ hours \end{lignes}$

<h3>From Statement 3,</h3>

Kai worked 8 hours in 1 day

$\begin{aligned}Time_3 &= 8\ hours \times 1\ days\\&= 8 \times 1\\&= 8\ hours \end{lignes}$

$\rm{Total\ work\ time\ of\ Kai = Time_2 +Time_3$

$= 24\ hours+8\ hours\\= 32\ hours$

<h2>Kai's hourly rate of pay</h2>

$\rm{Kai's\ hourly\ rate\ of\ pay =\dfrac{weekly\ paycheck\ of\ Kai}{Total\ work\ time \of\ Kai}$

$=\dfrac{\$616}{32\ hours}\\\\= \$19.25/hour$

Hence, Kai's hourly rate of pay is $19.25/hour.

Learn more about Rate of pay:

brainly.com/question/14000309

You might be interested in

List the steps to the following equation 5x - 6 = 44 then solve for x

Misha Larkins [42]

Add 6 to both sides so the -6 cancels out then divide the 38 you will get from 44-6 by 5 (38/5) to get your answer

5 0

3 years ago

Read 2 more answers

I need help with this question?????

tangare [24]

Its just multiplied by 2

3 0

3 years ago

Read 2 more answers

A B C or D help fast please!!!!

vodka [1.7K]

Answer:

c I just saw ur question sorry if I too late

4 0

3 years ago

You have at most 60 minutes to spend in the gym and in the pool. You want to spend more than 30 minutes in the gym and at most 1

Oksi-84 [34.3K]

I don’t really know I just need some points sry

3 0

2 years ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago