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NeX [460]
2 years ago
10

John buys an item that costs $50.00 is marked 20% off. Sales tax for the item is 8%. What is the final price that John pays, inc

luding tax?
Mathematics
1 answer:
bezimeni [28]2 years ago
7 0

Answer:

$43.20

Step-by-step explanation:

20% of $50.00 is $10.00. $50 - $10 is $40. 8% of $40 is $3.20. Since this is tax, you must add it. $40+$3.20 = $43.20

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6 hrs it took to change
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Identify the missing symbol<br>2√15?√60
madreJ [45]
X + 7x = 56 + 8

Simplifying x + 7x = 56 + 8 Combine like terms: x + 7x = 8x 8x = 56 + 8 Combine like terms: 56 + 8 = 64 8x = 64 Solving 8x = 64 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Divide each side by '8'. x = 8 Simplifying x = 8
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3 years ago
Find the number of terms in the series for the series given below.
Ratling [72]
C . bc its the right answer :)

7 0
2 years ago
If f(5) = 3.7 and f(6) = 8.7...<br> f(7) =<br> f(8) =<br> Recursive Function Is
Hitman42 [59]

Answer:

f(7) = 13.7

f(8) = 18.7

Recursive Function Is: f(1) = -16.3; (fn) = f(n - 1) + 5

Step-by-step explanation:

The recursive function of the arithmetic sequence is

f(1) = first term; f(n) = f(n-1) + d, where

  • d is the common difference between each two consecutive terms

∵ f(5) = 3.7 and f(6) = 8.7

∵ d = f(6) - f(5)

∴ d = 8.7 - 3.7

∴ d = 5

∵ f(7) = f(6) + 5

∴ f(7) = 8.7 + 5

∴ f(7) = 13.7

∵ f(8) = f(7) + 5

∴ f(8) = 13.7 + 5

∴ f(8) = 18.7

→ To find f(1) subtract from each term the value of d

∵ f(5) = f(4) + d

∴ f(4) = f(5) - d

∴ f(4) = 3.7 - 5

∴ f(4) = -1.3

∵ f(3) = f(4) - 5

∴ f(3) = -1.3 - 5

∴ f(3) = -6.3

∵ f(2) = f(3) - 5

∴ f(2) = -6.3 - 5

∴ f(2) = -11.3

∵ f(1) = f(2) - 5

∴ f(1) = -11.3 - 5

∴ f(1) = -16.3

∴ Recursive Function Is: f(1) = -16.3; (fn) = f(n - 1) + 5

6 0
2 years ago
Determine the coefficient of x^3 in the expansion of (1 – x)^5(1 + 1/x)^5
Mkey [24]

Notice that

(1 - <em>x</em>)⁵ (1 + 1/<em>x</em>)⁵ = ((1 - <em>x</em>) (1 + 1/<em>x</em>))⁵ = (1 - <em>x</em> + 1/<em>x</em> - 1)⁵ = (1/<em>x</em> - <em>x</em>)⁵

Recall the binomial theorem:

\displaystyle(a+b)^n = \sum_{k=0}^n\binom nk a^{n-k}b^k

Let <em>a</em> = 1/<em>x</em>, <em>b</em> = -<em>x</em>, and <em>n</em> = 5. Then

\displaystyle\left(\frac1x-x\right)^5 = \sum_{k=0}^5\binom5k\left(\frac1x\right)^{5-k}(-x)^k = \sum_{k=0}^5 (-1)^k\binom5k x^{2k-5}

We get an <em>x</em> ³ term for

2<em>k</em> - 5 = 3   ==>   2<em>k</em> = 8   ==>   <em>k</em> = 4

so that the coefficient would be

(-1)^4\dbinom54 = \boxed{5}

4 0
2 years ago
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