Given:
The function is
To find:
The asymptotes and zero of the function.
Solution:
We have,
For zeroes, f(x)=0.
Therefore, zero of the function is 0.
For vertical asymptote equate the denominator of the function equal to 0.
Taking square root on both sides, we get
So, vertical asymptotes are x=-4 and x=4.
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.
Answer: B) increasing for x < -4/3 and x > 4/3
decreasing for -4/3 < x < 4/3
<u>Step-by-step explanation:</u>
Graph the equation and follow the curve from left to right. If you are going up, it is increasing. If you are going down, it is decreasing.
Refer to the image below. Red is increasing. Blue is decreasing.
The vertices are at: x = -4/3 and x = 4/3
Then its midpoint = (-2, 3)
Answer:
C. -3/4, -2/3, 1/5
Step-by-step explanation:
Just from observation, you can tell the 1/5 will be the greatest because all the other fractions are negative. Then, I converted them to decimal form to make it easier.
-2/3 = -0.6666666 (the 6 goes on forever)
-3/4 = -0.75
1/5= 0.20
Then, you put them in order.
-3/4 would be the least .
Followed by, -2/3
Finally, 1/5
