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il63 [147K]
3 years ago
15

1/3(12u-2) please help me solve

Mathematics
1 answer:
jeka943 years ago
8 0

Answer:

u = 1/6

Step-by-step explanation:

<u>1</u> (12u - 2 )= 0

3

3×<u>1</u> (12u-2) =0×3

3

12u -2 =0

<u>12u</u> = <u>2</u>

12 12

u = <u>1</u>

6

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Answer:(b). 4I2-81

Step-by-step explanation:(2I+9)(2I-9)

=4I2-18I+18I-81

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Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10
natka813 [3]

ANSWER

( \frac{2}{3} , \frac{1}{5} )

EXPLANATION

The first equation is

\frac{1}{2} x -  \frac{3}{4} y =  \frac{11}{60} ...(1)

The second equation is

\frac{2}{5} x  +  \frac{1}{6} y =  \frac{3}{10} ...(2)

We want to eliminate y, so we multiply the first equation by

\frac{4}{5}

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We now subtract equation (3) from (2)

(\frac{2}{3} x  -  \frac{2}{3} x )+ ( \frac{1}{6} y -  -  \frac{3}{5}y ) =(  \frac{3}{10}  -  \frac{11}{75} )

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Multiply both sides by

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Substitute into the first equation to solve for x .

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Multiply to obtain

\frac{1}{2} x -  \frac{3}{20} =  \frac{11}{60}

\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}

\frac{1}{2} x = \frac{1}{3}

Multiply both sides by 2.

2 \times \frac{1}{2} x =2 \times  \frac{1}{3}

x = \frac{2}{3}

The solution is

( \frac{2}{3} , \frac{1}{5} )

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