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suter [353]
4 years ago
9

A mathematical formula designed to predict population fluctuations in a community could be called a(an)

Mathematics
1 answer:
kvasek [131]4 years ago
5 0
It would be called an ecological model.
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Which expression is equivalent to
Schach [20]

Answer:

equivalent to what? is there a missing picture?

Step-by-step explanation:

6 0
3 years ago
Riley is currently 4 times as old as her brother. If Riley was 11 years old 5 years ago, how old is Riley's brother now?
Sonbull [250]
Riley's age = r
Riley's brother's age = r/4

If Riley was 11 five years ago, Riley is currently 11 + 5 years old, or 16 years old.

Now we just need to use r/4 to find Riley's brother's age:

16 /4 = 4

Riley's brother is 4 years old.

Hope this helps!
5 0
4 years ago
about 7.5 gallons of water will fill up 1 cubic foot of space. how many gallons of water will fill a goldfish pool shaped like t
Cloud [144]
Well, since there is no image I am unable to say the exact volume. But here is the volume formula-
V=L times W times H
*V=volume W=width H=height
and you don't actually have to write times you can do the symbol.

Example- if I had a rectangular prism of the width being 5 cubes, the length 8 cubes, and the height 7 cubes(following how many gallons are in a cube 7.5) I would the use my formula. V=LWH- 8 times 7= 56 56 times 5=280 280 times 7.5= 2100
V=2100 (that is your answer reply If you didn't mean the volume or you don't get it)


7 0
3 years ago
Read 2 more answers
PLEASE HELP PLEASE WILL MARK BRAINLY
Shtirlitz [24]

Answer:

Every 18 miles he uses 3 gallons

divide this:

18 ÷ 3 = 6 miles per gallon

30 miles = 30 ÷ 6 = 5 gallons

7 gallons = 7 x 6 = 42 miles

48 miles = 48 ÷ 6 = 8 gallons

10 gallons = 10 x 6 = 60 miles

Hope this helps :D

8 0
3 years ago
Read 2 more answers
4. Use the process outlined in the lesson to approximate the number 2√3. Use the approximation √3 ≈ 1.732 050 8.
jeka57 [31]

Answer:

sequence of five intervals

(1) 2  < 2^{\sqrt{3} }   < 2^{2}

(2) 2^{1.7}  < 2^{\sqrt{3} }    < 2^{1.8}

(3) 2^{1.73}  < 2^{\sqrt{3} }    < 2^{1.74}

(4) 2^{1.732}  < 2^{\sqrt{3} }    < 2^{1.733}

(5) 2^{1.7320}  < 2^{\sqrt{3} }    < 2^{1.7321}

Step-by-step explanation:

as per question given data      

√3 ≈ 1.732 050 8 

to find out      

sequence of five intervals

solution      

as we have given that √3 value that is here

√3 ≈ 1.732 050 8            ........................1

so  

when we find 2^{\sqrt{3} }           ................2

put here √3 value in equation number  2  

we get  2^{\sqrt{3} }   that is  3.322    

so    

sequence of five intervals

(1) 2  < 2^{\sqrt{3} }   < 2^{2}

(2) 2^{1.7}  < 2^{\sqrt{3} }    < 2^{1.8}

(3) 2^{1.73}  < 2^{\sqrt{3} }    < 2^{1.74}

(4) 2^{1.732}  < 2^{\sqrt{3} }    < 2^{1.733}

(5) 2^{1.7320}  < 2^{\sqrt{3} }    < 2^{1.7321}

8 0
3 years ago
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