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Jobisdone [24]
3 years ago
8

passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to ?

Mathematics
2 answers:
cluponka [151]3 years ago
5 0

Answer: -5x -3y = 0

Step-by-step explanation:

took on edmentum/plato and got it right. enjoy :)

goblinko [34]3 years ago
4 0

Answer:

       Equation of line , 5x + 3y = 0

Step-by-step explanation:

The slope of a line passing through points (x₁,y₁) and (x₂,y₂) is given by \frac{y_2-y_1}{x_2-x_1}

Here points are given by (-3,0) and (-6,5)

Slope=\frac{5-0}{(-6)-(-3)}=\frac{-5}{3}

The slope of parallel lines are same. So slope of required line =\frac{-5}{3}

Equation of a line with slope m passing through origin is given by

                    y =mx

               So equation of line, y=\frac{-5}{3}x\\\\3y=-5x\\\\5x+3y=0

Equation of line , 5x + 3y = 0

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