Question

Someone help me please. I need my work submitted by 4:00

Answer 1

Answer:

$B.\ (-1.4z+0.4)\times 40 \\\\D.\ (8z-4)(-7)$

Step-by-step explanation:

Given the expression:

$-56z+28$

#We introduce a bracket and a common divisor:

Since 7 is a divisor of both numbers, we rewrite the expression as:

$-56z+58=-7(8z-4)\\\\=(8z-4)(-7)$

#We then introduce a second common divisor, 40:

$-56z+28=\frac{1}{40}\times-56z+28\times \frac{1}{40}\\\\=40(-1.4z+0.7)$

Hence, the expression can be rewritten as 40(-1.4z+0.4) and (8z-4)(-7)