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german
3 years ago
10

The following shapes are congruent. Write the correct congruence statement for shape MJZP.

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

B. LXYB.

Step-by-step explanation:

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PLEASE HELP I DON'T UNDERSTAND! A florist is making regular bouquets and mini bouquets. The florist has 118 roses and 226 peonie
Anna [14]

Answer:

The florist can make 11 regular bouquets and 21 mini bouquets

Step-by-step explanation:

The number of roses the florist has = 118 roses

The number of peonies the florist has = 226 peonies

The number of roses in each regular bouquet = 5 roses

The number of peonies in each regular bouquet = 11 peonies

The number of roses in each mini bouquet = 3 roses

The number of peonies in each mini bouquet = 5 peonies

1. The equation that gives the total number of roses to be used in both kinds of bouquet is given as follows;

Let r represent the number of regular bouquet the florist can make and let m represent the number of mini bouquet the florist can make, we have;

5·r + 3·m = 118...(1)

2. Similarly, we have;

11·r + 5·m  = 226...(2)

Making m the subject of the formula of both equations, and equating both values of m to find a common solution, we have;

m = (118 - 5·r)/3

m = (226 - 11·r)/5

(118 - 5·r)/3 = (226 - 11·r)/5

5 × (118 - 5·r) = 3 × (226 - 11·r)

590 - 25·r = 678 - 33·r

33·r - 25·r = 678 - 590 = 88

8·r = 88

r = 88/8 = 11

r = 11

The number of regular bouquet the florist can make = r = 11

m = (118 - 5·r)/3 = (118 - 5×11)/3 = 21

m = 21

The number of mini bouquet the florist can make = m = 21

The number of regular bouquet the florist can make = 11 bouquets

The number of mini bouquet the florist can make = 21 bouquets.

3 0
3 years ago
Represent real-world situations a rectangular piece of sheet metal is rolled and riveted to form a circular tube that is open at
Citrus2011 [14]
<span>12.3 Volume function: v(x) = ((18-x)(x-1)^2)/(4pi) Since the perimeter of the piece of sheet metal is 36, the height of the tube created will be 36/2 - x = 18-x. The volume of the tube will be the area of the cross section multiplied by the height. The area of the cross section will be pi r^2 and r will be (x-1)/(2pi). So the volume of the tube is v(x) = (18-x)pi((x-1)/(2pi))^2 v(x) = (18-x)pi((x-1)^2/(4pi^2)) v(x) = ((18-x)(x-1)^2)/(4pi) The maximum volume will happen when the value of the first derivative is zero. So calculate the first derivative: v'(x) = (x-1)(3x - 37) / (4pi) Convert to quadratic equation. (3x^2 - 40x + 37)/(4pi) = 0 3/(4pi)x^2 - (10/pi)x + 37/(4pi) = 0 Now calculate the roots using the quadratic formula with a = 3/(4pi), b = -10/pi, and c = 37/(4pi) The roots occur at x = 1 and x = 12 1/3. There are the points where the slope of the volume equation is zero. The root of 1 happens just as the volume of the tube is 0. So the root of 12 1/3 is the value you want where the volume of the tube is maximized. So the answer to the nearest tenth is 12.3</span>
3 0
3 years ago
ASAP PLZ HELP WILL MARK BRAINLIST IF U WANT TO FIRST PERSON WHO ANSWERS RIGHT
photoshop1234 [79]

Answer:

15.0

Step-by-step explanation:

Square root entire equation (-8 - 7)^2 + (-5 + 4)^2

8 0
3 years ago
Read 2 more answers
3x²-30x+9=0<br> PLEASE HELP<br> COMPLETING THE SQUARE WILL MARK BRAINLIEST
nlexa [21]

Answer:

i have done the cutting of x's exponent

Step-by-step explanation:

= 3x - 30+9 =0

= 3x - 21 =0

= 3x= 21

= x = 21/3

x= 7 this the answer

7 0
3 years ago
Answer question and show work please
SCORPION-xisa [38]
The recipes include: \frac{1}{2}\frac{3}{8}\frac{3}{10}
finding their lcm gives:
\frac{12,20,15}{40}
arranging them 
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please mark as brainliest
5 0
3 years ago
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