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Angelina_Jolie [31]
2 years ago
15

For the following inequality, find a solution for the variable. Show all of your work and use complete sentences to explain the

solving process that you used to find a solution for the inequality. Be sure to include at least two terms from the word bank
1/4 x \leq -3
Mathematics
1 answer:
AURORKA [14]2 years ago
6 0

Answer:

x<=-12

Step-by-step explanation:

1/4x<=-3

*Multiply both sides by 4

x<=-12

<em>and it's solved :)</em>

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What is the y value when x equals 21? y=310-25(x)​
Sati [7]

Answer:

Step-by-step explanation:

You subtract 310 from 25 and get 285 then you multiply 285 x 21 and I believe that should solve this equation.

8 0
3 years ago
Use a proportion to estimate each population. (Please solve both questions, thank you) (I’ll reward you with brainliest :)
hammer [34]

Answer:

<em>Step-by-step explanation:</em>

<em>Step 1. (The capture) Capture a sample  total counted =958, and them back tagged counted=38,total tagged=56 </em>

<em>The idea is to estimate the proportion p = m/N of tagged =102. </em>

<em>Step 2. (The recapture) After everything has settled down, capture a new sample of n fish. Count the number of tagged fish. Suppose that k of them are tagged. </em>

<em>It is reasonable that, k/n would be a good estimante for p = m/N. </em>

<em>Accordingly, for an estimate N of N, se solve the equation m/N= k/n. </em>

7 0
3 years ago
The rectangular coordinates of a point are given. Find the polar coordinates ​(r,theta​) of this point with theta expressed in r
alexandr402 [8]

Answer:}

In polar coordinates P is

P  ( 12 ; 2.618 )  

Step-by-step explanation:

The point (ectangular coordinates)  

P ( -6√3  ;   6 )       P  (  x ; y )

Polar coordinates   P ( r  ;  θ )

x = r cos θ

y = r sin θ                  r > 0    and     0  ≤ θ ≤ 2π

Then

r  =  √ (x)² + (y)²        r  =  √(36)²*3 +( 36)²       r = √144

r  =  12   (hypothenuse module always positive)

The point   P  ( -6√3  ;   6 )   is in second cuadrant  between 90° and 180°

angle between  r  and horizontal axis x  is equal to θ

tan α =  l.opp/ l.adj.    tan θ =  y/x       tan θ = - 6 /6√3

tan α = - 1/√3

Then α  =  180⁰ - 150⁰  = 30⁰  or     θ =  150⁰

to express that value in radians we have :

1 π radian      =   180⁰         ⇒   3,1416   radians  =  180⁰

                                                      x ??                  =   150⁰

x =  radians

Finally the point is   P  ( 12 ; 2.618 )  

6 0
3 years ago
A student earned grades of Upper AA​, Upper DD​, Upper AA​, Upper CC​, and Upper BB. Those courses had the corresponding numbers
dmitriy555 [2]

Answer:

  • The grade point average is 2.92
  • The student didn't make the​ Dean's list because the​ student's GPA is less than 3.0

Step-by-step explanation:

  • I take the grades as A,D,A,C,B not AA​,DD​,AA​,CC​,BB.
  • I take numbers of credit hours as 4,2,2,3,1 not as 44​, 22​, 22​, 33​, and 11.

Since quality points to letter grades are A=​4; B=​3; C=​2; D=​1; F=0, weighted mean is the sum of the qulity points times corresponding credit hours divided by the total credit hours:

\frac{(4*4) + (1*2) + (4*2) + (2*3) + (3*1)}{12} ≈ 2.92

Since 2.92<3.0, the student is not in Dean's list.

8 0
3 years ago
Please help me solve the problem
zavuch27 [327]

Answer:

f(2) = 7/4

Step-by-step explanation:

f(x) =  \frac{2x + 7 -  {x}^{2} }{4}  \\ f(2) =  \frac{2(2) + 7 -  {2}^{2} }{4}  \\ f(2) =  \frac{4 +  7- 4}{4}  \\ f(2) =  \frac{7}{4}

3 0
3 years ago
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