1 year ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

Mathematics

1 answer:

S_A_V [24]1 year ago

5 0

Answer:

8^2 = b^2 + 4^2

Step-by-step explanation:

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Find the altitude of a cylinder with with a radius of 9 and a surface area of approximately 791.68 units2.

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In this question , it is given that we have a cylinder with with a radius of 9 and a surface area of approximately 791.68 units square.

The formula of surface area of cylinder is

$A= 2 \pi r^2 + 2 \pi r h$

Substituting the values of A and r, we will get

$791.68 = 2* \pi * 9^2 + 2 * \pi * 9*h
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791.68 = 162 \pi + 18 \pi h
\\
791.68 -162 \pi = 18 \pi h
\\
h = \frac{791.68 -162 \pi}{18 \pi}
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h =5 units$

So the height of the cylinder is 5 units .

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What is the vertex form of Y = x2 - 6x + 6?

ahrayia [7]

Answer:

$\large\boxed{y=(x-3)^2-3}$

Step-by-step explanation:

The vertex form of a quadratic equation y = ax² + bx + c:

y = a(x - h)² + k

(h, k) - coordinates of a vertex

We have the equation y = x² - 6x + 6.

Convert to the vertex form:

$y=x^2-2(x)(3)+6\\\\y=\underbrace{x^2-2(x)(3)+3^2}_{(*)}-3^2+6\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\qquad(*)\\\\y=(x-3)^2-9+6\\\\y=(x-3)^2-3\to h=3,\ k=-3$

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