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2 years ago

If (2) - 2x - 6, which of these is the inverse of x)?

Mathematics

1 answer:

Romashka [77]2 years ago

7 0

Answer:

Step-by-step explanation:

y=-2x+6.

since it is inverse the gradient has to be the opposite of the base equation : y =2x-6.

dont forget to put it as the brainliest answer if it helps.

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At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The num

Viktor [21]

The given equations satisfy the given conditions. There are 2 equations and 2 unknowns, so a certain solution can be found.

This can be solved using substitution,

Substituting eqn 2 to eqn 1:

2(2y – 10) + 3y =1240

Simplifying,

y = 180

x = 350

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3 years ago

An avid traveler is investigating whether travel websites differ in their pricing. She chooses a random sample of 32 hotel rooms

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2 years ago

If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

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3 years ago

I have 3/5 of work and i complete 1/5 how much is left

9966 [12]

I hope this helps you

3/5-1/5=2/5

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3 years ago

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nydimaria [60]

200+90+8+.02 is the correct answer

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3 years ago