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AlexFokin [52]
2 years ago
6

Evaluate the following.​

Mathematics
2 answers:
lisov135 [29]2 years ago
7 0

Answer:

a. 7

b. 0

c. 4

d. 15

Step-by-step explanation:

the negative numbers in the absolute value get changed to positive.

Tju [1.3M]2 years ago
7 0

Step-by-step explanation:

1) 3 + 4 = 7

2) 6 - 6 = 0

3) 1 + 3 = 4

4) 6 + 9 = 15

5) 10 - 14 + 2 = -2

6) 2 + 3 - 5 = 0

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Evaluate -3x³-4x for x=-1​
anyanavicka [17]

Answer:

7

Step-by-step explanation:

Sub -1 in for each x:

-3x³-4x

-3(-1)³-4(-1)

-3(-1)+4

3+4

7

4 0
3 years ago
Read 2 more answers
Need help on edge 6th grade math
MatroZZZ [7]

Answer: a, 7ft

Step-by-step explanation:

8 0
2 years ago
Add and SImplify<br> (x+2)/(x) + (x-3)/(x+2)
Jlenok [28]
(x+2)/(x) + (x-3)/(x+2)

Common denominator x(x+2)

Reduce both to common denominator:
x+2)/[x(x+2)] + (x-3)/[x(x+2)] ===> [(x+2)² + (x-3)] / [x(x+2)]
= [x²+4x+4+x-3] / [x(x+2)]
=[x²+54x+1] / [x(x+2)]
7 0
3 years ago
For each expression listed, is it a difference of squares? Explain yes or no and why or why not. Explain in enough detail so the
Harlamova29_29 [7]
<h2>Explanation:</h2><h2></h2>

If we can write a polynomial in the form a^2-b^2, then we can factor it as:

a^2-b^2=(a-b)(a+b)

In this problem, we have the following expressions:

1. \ y^5 - 25 \\ \\  2. \ 9m^2n^2-121  \\ \\ 3. p^{18} - q^{10} \\ \\ 4. 16r^2 - 27

  • For 1 and 4 we can't write this in the form a^2-b^2 so this is not a difference of squares.

  • For 2:

9m^2n^2-121 =3^2m^2n^2-11^2 \\ \\ =(3mn)^2-11^2 =(3mn-11)(3mn+11)

So we could write 2 as a difference of squares.

  • For 3:

p^{18} - q^{10}=(p^9)^2-(q^5)^2=(p^9-q^5)(p^9+q^5) \\ \\ \\ Remember: \ (a^m)^n=a^{mn}

So we could write 2 as a difference of squares.

7 0
3 years ago
I need help with #10 please! Thanks!
Anastasy [175]
√27 can be simplified. First we split it into √9√3 because 9*3=27. Now the √9 becomes 3. We can multiply this 3 with the 3 in the beginning of the problem to get 9√3 as the final answer

Hope this helps
7 0
3 years ago
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