Answer:
C ≈ 22.1°
Step-by-step explanation:
The law of cosines formula is given. Solving it for C, we find ...
C = arccos((a^2 +b^2 -c^2)/(2ab))
where a and b are the sides adjacent to the angle.
Then we have ...
C = arccos((14^2 +19^2 -8^2)/(2·14·19)) = arccos(493/532)
C ≈ 22.1°
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If you have a fair number of these to do, a spreadsheet is a useful tool. There are also triangle solver apps on the web or your local smart platform that will do this, too.
Answer:
the height of the flagpole is three fourths the height of the school. the difference in there heights is 4.5 m. what is the height of the school?
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Equation:
f = (3/4)s
s-f = 4.5
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Substitute for "f" and solve for "s":
s-(3/4)s = 4.5
(1/4)s = 4.5
s = 4*4.5
s = 18 meters (height of the school)
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Since f = (3/4)s, f = (3/4)(18)
= (3/2)(9)= 13.5 meters (height of the flag pole)
===============================-step explanation: HOPE THIS HELPS
Answer:
x = -6, y = -2
Step-by-step explanation:
2x-7y = 2
3x + y = -20
We need to cancel out either x or y to solve the equation. I'll cancel out x first
3(2x-7y = 2)
-2(3x+y=-20)
___________
6x-21y = 6
-6x -2y = 40
____________
-23y = 46
y = -2
Plug the value for y in one of the 2 equations to solve for x
2x -7(-2) = 2
2x+14=2
2x = -12
x=-6
Answer:
alternate exterior angles and corresponding angles
