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Orlov [11]
3 years ago
10

2x - 7y = 2 and 3x + y = -20 addition/elimination

Mathematics
1 answer:
Mkey [24]3 years ago
6 0

Answer:

x = -6, y = -2

Step-by-step explanation:

2x-7y = 2

3x + y = -20

We need to cancel out either x or y to solve the equation. I'll cancel out x first

3(2x-7y = 2)

-2(3x+y=-20)

___________

6x-21y = 6

-6x -2y = 40

____________

-23y = 46

y = -2

Plug the value for y in one of the 2 equations to solve for x

2x -7(-2) = 2

2x+14=2

2x = -12

x=-6

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\sqrt{5x} + √6 = √9


The first step is to get \sqrt{5x} by itself. We can do this by subtracting \sqrt{6} from each side, and simplifying \sqrt{9}


\sqrt{5x} = 3 - \sqrt{6}


Now we square both sides


5x = (3 - \sqrt{6})²


Using the formula (a - b)² = a² -2ab + b², (3 - \sqrt{6})² = 15 - 6\sqrt{6}


5x = 15 - 6\sqrt{6}


x = \frac{15 - 6\sqrt{6}}{5}

8 0
3 years ago
Read 2 more answers
-3x+3y=3<br> -5x+y=13<br> Solve for substitution
vladimir1956 [14]
Take -5x + y =13 and rearrange for y:
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Substitute into other equation for y:
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Simplify:
12x+39=3

Rearrange for x:
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Substitute back into y=13+5x:
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