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3 years ago

2x - 7y = 2 and 3x + y = -20 addition/elimination

Mathematics

1 answer:

Mkey [24]3 years ago

6 0

Answer:

x = -6, y = -2

Step-by-step explanation:

2x-7y = 2

3x + y = -20

We need to cancel out either x or y to solve the equation. I'll cancel out x first

3(2x-7y = 2)

-2(3x+y=-20)

___________

6x-21y = 6

-6x -2y = 40

____________

-23y = 46

y = -2

Plug the value for y in one of the 2 equations to solve for x

2x -7(-2) = 2

2x+14=2

2x = -12

x=-6

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M/IGF = 135x, m/HGF = 161°, and m/HGI = 26x. Find x

Nina [5.8K]

Answer:

x = 1

Step-by-step explanation:

The two angles, ∠HGI & ∠IGF, when combined, will result in ∠HGF.

Note:

m∠IGF = 135x

m∠HGI = 26x

m∠HGF = 161°

Set the equation:

m∠IGF + m∠HGI = m∠HGF

Plug in the corresponding terms to the corresponding variables:

135x + 26x = 161

Combine like terms:

(135x + 26x) = 161

161x = 161

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Divide 161 from both sides:

(161x)/161 = (161)/161

x = 1

1 is your answer.

x = 161/161 = 1

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2 years ago

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torisob [31]

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2 years ago

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The dimensions of rectangle A are four times the dimensions of rectangle B. The area of rectangle B is 162 cm2. What is the area

Anna [14]

Answer:

2,592 square cm.

Step-by-step explanation:

It is given that the dimensions of rectangle A are four times the dimensions of rectangle B.

Let dimensions of rectangle B are l×b.

So, the dimensions of rectangle A are 4l×4b.

Area of rectangle is

$Area=length\times width$

Area of rectangle B is

$A_B=l\times w$

The area of rectangle B is 162 square cm.

$A_B=l\times w=162$

Area of rectangle A is

$A_A=4l\times 4w=16(l\times w)=16(162)=2592$

Therefore, the area of rectangle A is 2,592 square cm.

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3 years ago

What would the following system of equations look like in augmented matrix form?

AlladinOne [14]

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3 years ago

In order to estimate the mean amount of time computer users spend on the internet each month, how many computer users must be s

Lyrx [107]

Answer:

832

Step-by-step explanation:

standard deviation =228 minute

error =13 minute given

confidence level =905% =0.90

α=1-0.90=0.1

$z_\frac{\alpha }{2}=z_\frac{0.1}{2}=1.645$

we know that sample size should be greater than

$n\geq \left ( z_\frac{\alpha }{2}\times \frac{\sigma }{E} \right )^2$

$n\geq \left ( 1.645\times \frac{228}{13} \right )^{2}$

$n\geq 28.850^2$

$n\geq 832.3668$

n=832

4 0

3 years ago