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2 years ago

Type the expression that results from the following series of steps:

Mathematics

1 answer:

Sever21 [200]2 years ago

3 0

6-z

Z-6 would be wrong because the question said start with 6

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How do you solve 75.25-11.92?

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Your answer would be 63.33. ((: ❤️

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3 years ago

According to a recent study, the average woman's leg hair grows an eighth of an inch per month. A new drug company believes that

Afina-wow [57]

Answer:

Step-by-step explanation:

Null hypothesis should be: The average woman's leg hair grows an eighth of an inch per month: u = eighth of an inch

Alternative hypothesis: The average woman's leg hair growth is not an eighth of an inch per month after treatment: u ≠ eighth of an inch

This test after carrying out its treatment will be able to determine if the drug was effective or not

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3 years ago

What is the value of n that would make the following radical expression true?

viktelen [127]

Answer: 3

Step-by-step explanation:

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2 years ago

Read 2 more answers

Mary has three baking pans. Each pan is 8" × 8" × 3". Which expression will give her the total volume of the pans?

klio [65]

The volume of one pan is 192 units cubed. The volume of the three pans is 576 units cubed.

7 0

3 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago