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3 years ago

In a jar, 25% of the marbles are red. If there are 45 red marbles in the jar, how many marbles are in the jar altogether?

Mathematics

2 answers:

Oxana [17]3 years ago

8 0

Answer:

There are 180 marbles in the jar

Step-by-step explanation:

Let x = number of marbles in the jar

x * 25% = number of red marbles

x * .25 = 45

Divide each side by .25

x *.25/.25 = 45/.25

x =180

There are 180 marbles in the jar

salantis [7]3 years ago

8 0

Answer:

Answer: 180 marbles

Step-by-step explanation:

25 percent can be converted to 1/4 and 4 x 1/4 = 1 and/or whole

Now since 45 marbles = 25 percent/1 /4 of WHAT is in the jar now we can multiple 45 x 4 (times 4 to make the 1/4 into a whole) which gives up 180 marbles total.

Hopefully I explained it in a way you can understand

Hope this helped

Step-by-step explanation:

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The radius of a circular merry-go-round is 3 meters. which measurement is closest to the area of the merry-go-round in square me

djyliett [7]

Answer:

area of the merry go round =πr²

=22/7×3²

=28.28

answer is option D

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3 years ago

use any strategy to solve the following problems 1) for haloween ned received 48 pieces of candy .if he put them into piles with

Veronika [31]

Answer:

He could make 16 piles.

Step-by-step explanation:

Divide 48 by 3: 48 ÷ 3 = 16

6 0

3 years ago

The average household income for a recent year was $30,000. five years earlier the average household income was $24,500. assume

ikadub [295]

Using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.

According to the question,

The average household income for a recent year (x₁⁻) = $30,000

The average household income for a recent year (x₂⁻) = $24,500

sample sizes n₁ = n₂ = 34

standard deviation of both samples were $24,500. Thus, s₁ = s₂ = $5928.

Null hypothesis: There is no evidence to believe that the average household income has increased.

H₀ : μ₁ ≤ μ₂

Alternative hypothesis: There is evidence to believe that the average household income has increased.

H₁: μ₁ > μ₂

To check hypothesis we have the formula

Standard error= $\sqrt{\frac{s_{1} ^{2} }{n_{1} } + \frac{s^{2} _{2} }{n_{2} } }$

= $\sqrt{2067128.4706}$

= 1437.7512

Thus, standard error is $1437.7512.

Formula for test statistic = [(x₁⁻ - x₂⁻) - (μ₁ - μ₂)]/standard error

= [(30000 - 24500) - 0]/1437.7512

= 3.8254

The critical value of z at 5% level of significance is 1.6449.

Here, the calculated value is greater than the critical value so we reject H₀.

Hence using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.

Learn more about hypothesis test here

brainly.com/question/15060525

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3 0

2 years ago

Which two values of x are roots of the polynomial below? x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

Solution:

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$

Hence, the roots of given polynomial are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

6 0

3 years ago

Write the expression as a square of a monomial 121a^6

Nutka1998 [239]

The square root of 121 is 11. The square toot of a^6 is a^3. Therefore 121a^6 can be expressed as (11a^3)^2, and 11a^3 is a monomial since it is a single term with nothing added or subtracted to it or from it. So 121a^6 as a squared monomial is (11a^3)^2.

5 0

3 years ago