1/2r -3= 3 (4-3/2r) is to be solved for r.
I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.
Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .
Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:
r -6 = 3 (4*2-(3)r ) or r - 6 = 24 - 9r
Now expand the right side, using the distributive property of
r - 3 = 24 - 9r
Regrouping so as to combine like terms:
10r = 30
Solving for r: r = 30/10 = 3
The value of r that satisfies this equation is 3
Answer:
(1-cosA)/(1+cosA)
=(1-cosA)/(1+cosA) ×(1-cosA)/(1-cosA)
=(1-cosA)^2 /(1-cos^2A)
=(1-cosA)^2 / (sin^2A)
=(1/sinA - cosA/sinA )^2
=cosecA - cotA)^2
Hope it helps
Have a great Day ; )
28/100 then simplify
14/50
