The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
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Answer:
it's probably b
Step-by-step explanation:
I don't know how to do it so don't do b
I’m not sure what the question is, so if you could tell me what the actual question is I might be able to answer it!
Answer:
<em>-</em><em>1</em>
Step-by-step explanation:
<em>x</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>unknown</em><em> </em><em>and</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>known</em><em> </em><em>as</em><em> </em><em><u>1</u></em><em><u> </u></em><em>or</em><em> </em><em><u>-</u></em><em><u>1</u></em><em><u> </u></em><em>based</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>circumstance</em><em>.</em><em> </em>
<em>Therefore</em><em>,</em><em> </em><em>in</em><em> </em><em>this</em><em> </em><em>case</em><em>,</em><em> </em><em>x</em><em> </em><em>is</em><em> </em><em>known</em><em> </em><em>as</em><em> </em><em><u>-</u></em><em><u>1</u></em>
4 x 8= 16+16 8 x 4 is 32 and 16-32 is 16 so the missing number is 16.
