I think that the answer is C.11
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Answer:
there are no signs between the x and y and constant
it could be
2x+5y=15
2x+5y=-15
-2x+5y=15
2x-5y=15
for ax+by=c, the equation of a line paralell to that is
ax+by=d where a=a, b=b, and c and d are constants
(for this answer, I'm going to use 2x+5y=15)
given 2x+5y=15, the equation of a line paralell to that is 2x+5y=d
to find d, subsitute the point (4,-2), basically put 4 in for x and -2 for y to get the constant
2x+5y=d
2(4)+5(-2)=d
8-10=d
-2=d
the eqaution is 2x+5y=-2 (Only if the original equation is 2x+5y=-15
pls mark me brainlest
Answer:
X is 24
Step-by-step explanation:
mark me brainliest!!!!
Answer:
x=0, y=3
x=5, y= 2
Step-by-step explanation:
(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))
Recall that
tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)
so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:
(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))
Recall the double angle identity for cosine,
cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1
so the 1 in the denominator also vanishes:
(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))
Recall the Pythagorean identity,
cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1
which means
sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):
-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))
Cancel the cos²(<em>θ</em>) terms to end up with
(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>)) = -1/2
