Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.
Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.
4.5, 4, 3.5, 3, 2.5, 2 and use the pencil and ruler, love a bit of MathsWatch
Answer: Choice B
A net is shown with a pentagon in the middle and 5 identical triangles on the 5 sides of the pentagon
The pentagon forms the base of the pentagonal pyramid. Each lateral side is a triangle that meets at the very top of the pyramid. The base stays on the floor while the sides are folded up.
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There are other possible net configurations to form a pentagonal pyramid, but the other answer choices do not make a pentagonal pyramid.
- Choice A produces a square pyramid.
- Choice C makes a triangular pyramid (aka tetrahedron).
- Choice D makes a hexagonal pyramid.
So we can rule choices A, C and D out.
Answer:
130279000000
Step-by-step explanation:
e+n=10^n
