We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Distribute
remember
a(b+c)=ab+ac
2(2.5q+8)=2(2.5q)+2(8)=5q+16
1-5q+5q+16
1+0+16
17
Answer:
y=-2x+10
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(8-(-10))/(1-10)
m=(8+10)/-9
m=18/-9
m=-2
------------------
y-y1=m(x-x1)
y-(-10)=-2(x-10)
y+10=-2x+20
y=-2x+20-10
y=-2x+10
The answer to the question <span>The coordinates of the endpoints of RT are R(-6,-5) and T(4,0), and point S is on RT. The coordinates of S are (-2,-3). Which of the following represents the ratio RS:ST? is B</span>
