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2 years ago

What 46821 to the nearest 100

Mathematics

2 answers:

borishaifa [10]2 years ago

4 0

46900 would be the answer

DanielleElmas [232]2 years ago

4 0

<h3>Answer: 46,800</h3>

Your teacher may want you to erase the comma when inputting your answer.

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Explanation:

Circle the digit in the hundreds place value, which is the digit 8. The next digit over is 2. This "2" is not five or larger, so we erase the "21" and replace it with "00".

The number 46,821 rounds to 46,800 which is the final answer.

Effectively, all we're doing is rounding the 821 to 800 and then sticking "46" in front. Notice how 821 is closer to 800 than it is to 900. So that's why we didn't round up to 46,900.

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A line with a slope of -4 passes through the point

Viktor [21]

Answer:

y = -4x - 22

Step-by-step explanation:

m = -4

using (-6,2)

Slope-intercept: y = mx + b

2 = -4(-6) + b

2 = 24 + b

b = -22

y = -4x - 22

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2 years ago

Write in y= mx + b form: a line through (-3,1) having the same y-intercept as the graph of x-2y=-4

MariettaO [177]

Step-by-step explanation:

Aight, so the same intercept

$- 2y = - 4 - x = = = > \\ y = \frac{1}{2} x + 2$

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2 years ago

Write the expression (X+6)(x-4) as a polynomial in standard form.

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3 years ago

Tell whether each question can be written in the form y = mx + b

Inessa [10]

Tell whether each question can be written in the form y = mx + b
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4 years ago

Media experts claim that daily print newspapers are declining because of Internet access. Listed below, from left to right and

yKpoI14uk [10]

Answer:

(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(d) The p value is 1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean, $\bar{x}_{1}$ = 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean, $\bar{x}_{2}}$ = 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

$t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}$

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic $t_{\alpha/2}$ = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

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3 years ago