Find the product

Luisa sells stuffed animals.she sells a stuffed elephant for $34.90, and the sale tax is 6% of the sale price.about how much is

Amiraneli [1.4K]

To solve this problem you must follow the proccedure below:

1. You have that Luisa sells a stuffed elephant for $34.90 and <span>the sale tax is 6% of the sale price.

2. Then, you only have to multiply</span> $34.90 by the sale tax, as below:

6/100=0.06

Sales tax on the elephant=$34.90x0.06
Sales tax on the elephant=$2.094
<span>
About how much is the sales tax on the elephant?
</span>
The answer is: $2.094

5 0

3 years ago

Which segment of the triangle will give you the height of your peak? Write the equation for the proportion that will allow you t

Novosadov [1.4K]

The segment that will give the height of the peak is the segment that is located from the right angle to the peak.
To find the height, we can use the fact that we have two similar triangles.
We are going to define a variable.
We have:
x: height of the peak.
For similar triangles, we have the following relationship:
$\frac{x}{20} = \frac{6}{3}$
From here, we clear the height of the peak
Answer:
the equation for the proportion that will allow you to find the height of your peak is:
$\frac{x}{20} = \frac{6}{3}$

8 0

4 years ago

(ASAP PICTURE ADDED) What is the simplified form of the following expression?

bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

$7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)$

WE need to simplify this equation.

Solve the parenthesis of each term.

$=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right$

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation: $=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)$

Adding like terms we get:

$=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\$