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2 years ago

What factors do 20 and 30 have in common? please help me:)

Mathematics

1 answer:

Vilka [71]2 years ago

8 0

Answer:

1, 2, 5, and 10

Step-by-step explanation:

Factors for 20 are:

1, 2, 4, 5, 10, 20

Factors for 30 are:

1, 2, 3, 5, 6, 10, 15, 30

You might be interested in

What is the equation of the line that passes through the point (-2,0) and has a slope of -2

Tcecarenko [31]

Answer:

y = -2x -4

Step-by-step explanation:

The equation of a line is y = mx + b, where m is the slope of the line, and b is the y-intercept. We are told that the slope of the line is -2, so we can start with

y = mx + b

y = -2x + b

We can figure out the value of b by plugging in the coordinates of the point given (-2, 0)

0 = -2(-2) + b

0 = 4 + b

Subtract 4 from both sides of the equation

-4 = b

Then plug that value of b back into the equation above:

y = -2x + (-4) or y = -2x -4

6 0

2 years ago

Read 2 more answers

Please and thank you

NemiM [27]

Y+3=1/4x-1/4
0.25x-y=3-0.25
0.25x-y=2.75

8 0

2 years ago

Britney bought 2 apples, 5 bananas, and 8 oranges at the grocery store.

Sladkaya [172]

Answer:

2 apples: 5 bananas: 8 oranges

Final answer: 1 apple: 2,5 bananas ( divide by 2 )

5 0

2 years ago

Read 2 more answers

A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

2 years ago

(50 POINTS)!

Yuliya22 [10]

Answer:

The answer to your question is below

Step-by-step explanation:

When a denominator has a positive exponent we change it into an expression with a negative exponent and vice-versa, when a numerator has a positive exponent, we change it into a denominator with a negative exponent.

a) $\frac{1}{p^{4}}$ = p⁻⁴

b) $\frac{1}{25}$ = 25⁻¹

4 0

2 years ago