Answer:
In order from least to greatest: 0.25, 3 ⅜, 3 <span>⅖</span>;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
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Explanation:
0.25 = ¼ l (less than "1"); the lowest of the three given values.
The remaining two values have the same whole number of 3, and a fraction:
3 <span>⅖ ;</span> and 3 ⅜.
The least common multiples among the denominators of the fraction values is 40. ⅖ = ?/40 ; 5*? =40? 5* 8 = 40, so 2*8 = 16;
Thus, ⅖ = 16/40, and 3 ⅖ = 3 16/40. 3/8 = ?/40? 8*5 =40; so 3*5 = 15 ; thus ⅜ = 15/40; and
and 3 ⅜ = 3 15/40.
3 15/40 is less than than 3 16/40;
as such; 3 ⅜ is less than 3 ⅖.
So, in order from least to greatest: 0.25, 3 ⅜, 3 ⅖;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
Answer:
B
Step-by-step explanation:
The line is solid, so eliminate A and D.
Also, the line is shaded below, so this eliminates C.
I assume you mean
ANSWER
An expression for P(t) is

EXPLANATION
This is a separable differential equation. Treat M and k as constants. Then we can divide both sides by M - P to get the P term with the differential dP and multiply both sides by dt to separate dt from the P terms
Integrate both sides of the equation.

Note that for the left-hand side, u-substitution gives us

hence why

Now we use
the definition of the logarithm to convert into exponential form.
The definition is

so applying it here, we get

Exponent properties can be used to address the constant C. We use

here:

If we assume that P(0) = 0, then set t = 0 and P = 0

Substituting into our original equation, we get our final answer of
Answer:
y- axis
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y )
Consider the corresponding vertices
A(- 1, - 1 ) → A'(1, - 1 )
B(- 2, - 1 ) → B'(2, - 1 )
C(- 2, - 4) → C'(2, - 4 )
These coordinates satisfy the condition for reflection in the y- axis
Answer:
a(n) = a(n-1) + 4
Step-by-step explanation:
a(1) = 2 The first term is 2
a(n) = a(n-1) + 4 We add 4 to the previous term or n-1
So, we get...
a(n) = a(n-1) + 4
a(1) = 2
a(2) = a(2-1) + 4 2(1) +4 = 6
a(3) = a(3-1) +4 3(2) + 4 = 10
and so on and so forth. I hope this helps.