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saveliy_v [14]
1 year ago
5

In traveling across flat land, you see a mountain directly in front of you. Its angle of elevation (to the peak) is 3.5°. After

you drive 19 kilometers closer to the mountain, the angle of elevation is 9° (see the following figure).
Approximate the height of the mountain (in kilometers). (Round your answer to one decimal place.)

Mathematics
1 answer:
yaroslaw [1]1 year ago
7 0

The height of the mountain is 0. 2 km

<h3>How to determine the height</h3>

First, let's find the hypotenuse of the second triangle

Using the tangent identity, we have;

tan θ = opposite/ adjacent

tan 3. 5 = x/ 19

cross multiply

x = tan 3 . 5 × 19

x = 0. 061 × 19

x = 1. 16 km

Now, we have the hypotenuse side of the second triangle and we need to find the opposite side which is the height of the mountain

Using the sine identity:

sin 9 = y/ 1.16

cross multiply

y = sin 9 × 1. 16

y = 0. 1564 × 1. 16

y = 0. 18 km

y = 0. 2 km in one decimal place

Thus, the height of the mountain is 0. 2 km

Learn more about angle of elevation here:

brainly.com/question/2004882

#SPJ1

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3 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
3 years ago
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