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kicyunya [14]
3 years ago
5

The product of two consecutive odd numbers is 10 more than the square of the smaller number. Find the smaller number

Mathematics
1 answer:
True [87]3 years ago
8 0

Answer:

5

Step-by-step explanation:

let the consecutive odd numbers be n and n + 2 , then

n(n + 2) = n² + 10 , that is

n² + 2n = n² + 10 ( subtract n² from both sides )

2n = 10 ( divide both sides by 2 )

n = 5

That is the smaller number is 5

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A circular pool with a diameter of 18 ft will have a uniform 4 ft concrete walkway poured around it. If the concrete cost $4.25 a square foot, how much will it cost for the concrete?

This can be solve be solving the area of walkway

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= 276.46 sq ft

Cost = 276.46 sq ft * ($4.25 a square foot) = $1174.70

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Reggie has a rectangular piece of paper that is 12 inches long and 7 inches wide. He is going to cut the paper from corner to co
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A property from geometry states that rectangles have congruent opposite sides. Thus, no matter which diagonal Reggie cuts, it still has the same lengths. Since it's a rectangle and we cut from corner to corner, we create a right triangle. See the picture below:

<u>___________12 inches_______</u>

7 |

i |

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Because it's a rectangle, it won't matter which corner we cut. But if we fold at the cut lines, we would make an in the rectangle's center.

The cut line and two sides make a right triangle. One leg is 12, one leg is 7, and we need to find the third side. The Pythagorean Theorem - sum of the squares of the legs equals the square of the hypotenuse - is applied.

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3 years ago
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
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Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

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<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

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We have

5^2+6^2=25+36=61,\\\\14^2=196.

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So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

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Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

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We have

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Therefore,

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So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

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