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3 years ago

In the figure below, AB is a diameters of circle P what is the arc measure of AD in degrees

Mathematics

2 answers:

rusak2 [61]3 years ago

6 0

Can I see a picture of the question

aliina [53]3 years ago

6 0

Answer:

Step-by-step explanation:

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Simplify: ^4square root 400/ ^4square root 5 show your work

Rainbow [258]

⁴√400 / ⁴√5 = 400^¼ / 5^¼
= (5 x 2²)² / 5^¼
= 5² x 2⁴ / 5^¼
= ⁴√5^7 x 2⁴

7 0

3 years ago

How are you supposed solve x

Sergeeva-Olga [200]

Because the lines are parallel, 75 is equal to 11x-2
75=11x-2
77=11x
x=7

7 0

3 years ago

Read 2 more answers

15x-7=2+12x I need help with this

Amanda [17]

Answer:

$\huge{ \boxed{ \bold{ \tt{x = 3}}}}$

<h3>♁ Question : Solve for x</h3>

15x - 7 = 2 + 12x

<h3>♁ Step - by - step explanation</h3>

$\text{15x - 7 = 2 + 12x}$

Move 12x to L.H.S ( Left Hand Side ) and change it's sign

➛ $\sf{15x - 12x - 7 = 2}$

Move 7 to R.H.S ( Right Hand Side) and change it's sign

➛ $\sf{15x - 12x = 2 + 7}$

Subtract 12x from 15x

Remember that only coefficients of like terms can be added or subtracted.

➛ $\sf{3x = 2 + 7}$

Add the numbers : 2 and 7

➛ $\sf{3x = 9}$

Divide both sides by 3

➛ $\sf{ \frac{3x}{3} = \frac{9}{3}}$

➛ $\boxed{ \bold{ \sf{x = 3}}}$

The value of x is $\boxed{ \sf{3}}$

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

☄ Now, let's check whether the value of x is 3 or not!

<h3>☥ Verification :</h3>

$\sf{15x - 7 = 2 + 12x}$

$\dashrightarrow{ \sf{15 \times 3 - 7 = 2 + 12 \times 3}}$

$\dashrightarrow{ \sf{45 - 7 = 2 + 36}}$

$\dashrightarrow{ \sf{38 = 38}}$

L.H.S = R.H.S ( Hence , the value of x is 3 ).

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

<h3>✒ Rules for solving an equation :</h3>

If an equation contains fractions ,multiply each term by the L.C.M of denominators.
Remove the brackets , if any.
Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
Simplify and get the single term on each side.
Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Have a wonderful time ! ツ

~TheAnimeGirl

5 0

2 years ago

The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.

denis-greek [22]

$\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b$

which means there is some integer $k$ for which $a+b=9k$ .

Because $9\mid a$ and $9\mid b$ , there are integers $n_1,n_2$ such that $a=9n_1$ and $b=9n_2$ , and

$\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42$

We have $42=2\cdot3\cdot7$ , which means there are four possible choices of $n_1,n_2$ :

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for $a,b$ :

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of $a+b$ is 117.

6 0

3 years ago

7k = 3k - 36<br> It’s gotta be a step by step equation

vovikov84 [41]

K=-9 Bc you move the variable to the left and then collect like terms and divide both sides

8 0

3 years ago