Answer:
x=2.5 or x=-4
Step-by-step explanation:
factorisation= factors:1, 2, 4, 5, 10, 20 (only the positive factors)
We will use the factors 4 and 5.
=(2x-5)(x+4)=0
2x-5=0 || x+4=0
2x=+5 || x=-4
x=2.5 or x=-4
Answer:
im sorry idontknow
Step-by-step explanation:
32 = 1 x 32, 2 x 16, or 4 x 8. Factors of 32: 1, 2, 4, 8, 16, 32
Hope I heled! :)
Answer:
I) 8.760 * 10 ³ hours
II) 8.76582 * 10 ³ hours
Step-by-step explanation:
1) No. of hours in one year:
24 hours* 365 days= 8760 hours
Scientific Notation= 8.760 * 10 ³ hours
2) 1 year = 31556952 seconds
1 hour=3600
1 year = 31556952 seconds/3600 = 8765. 82 hours
Scientific Notation= 8.76582 * 10 ³ hours
3) The exact numbers of hours using 365 days is 8760 which is written as 8.760* 10 ³ in scientific notation. But using the given data we get =8.76582 * 10 ³ hours
Comparing these answers the first one has only 3 significant figures
But the second answer has six significant figures if we round these we get 8.8 * 10 ³ hours which has two significant numbers
Aslo rounding the first gives 8.8 * 10 ³ hours which has two significant numbers and is the same as the other answer rounded
Given the function f(x);

Evaluating the function f(x+h);

So;

Evaluating the second function;

simplifying further;

Therefore, we have;