First solve for the slope, m using the two points given. It doesn't matter which point you choose as point 1 or 2 as long as you're consistent.
m = (y2 - y1)/(x2 - x1)
point 1: (–6.4, –2.6)
point 2: (5.2, 9)
m = (9 - -2.6)/(5.2 - -6.4)
m = (9 + 2.6)/(5.2 + 6.4)
m = 11.6/11.6
m = 1
put the newly found slope into the linear equation for m
y = (1)x + b
y = x + b
Now solve for the y-intercept, b
by putting one of the given points
9 = 5.2 + b
b = 9 - 5.2
b = 3.8
final equation:
y = x + 3.8
2x = Twice your age
200 = Two hundred less
> -1 = more than negative
With the information given, your equation would be:
200-2x>-1
<h2>
Answer with explanation:</h2>
It is given that:
f: R → R is a continuous function such that:
∀ x,y ∈ R
Now, let us assume f(1)=k
Also,
( Since,
f(0)=f(0+0)
i.e.
f(0)=f(0)+f(0)
By using property (1)
Also,
f(0)=2f(0)
i.e.
2f(0)-f(0)=0
i.e.
f(0)=0 )
Also,
i.e.
f(2)=f(1)+f(1) ( By using property (1) )
i.e.
f(2)=2f(1)
i.e.
f(2)=2k
f(m)=f(1+1+1+...+1)
i.e.
f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)
i.e.
f(m)=mf(1)
i.e.
f(m)=mk
Now,

Also,
i.e. 
Then,

(
Now, as we know that:
Q is dense in R.
so Э x∈ Q' such that Э a seq
belonging to Q such that:
)
Now, we know that: Q'=R
This means that:
Э α ∈ R
such that Э sequence
such that:

and


( since
belongs to Q )
Let f is continuous at x=α
This means that:

This means that:

This means that:
f(x)=kx for every x∈ R
Answer:
798.15
Step-by-step explanation:
heres a neat trick you can do instead of doing that long process to get 15% of 5321 just use a calculator and do 5321 x .15