Answer:
Therefore the value of x is 5.
Step-by-step explanation:
Given:
△ABC ≅ △DEF,
EF = x 2 - 7, and
BC = 4x - 2.
To Find:
the values of x. = ?
Solution:
△ABC ≅ △DEF ........Given
If two Triangles are congruent then the Corresponding Parts of Congruent Triangles are Congruent.
∴ BC ≅ EF ...................CPCTC
Substituting the values we get

Now By Factorizing we get

Therefore the value of x is 5.
42/7 =6 she planted 6 in each row
You problem is you don't have any problem. You have a bunch of formulas for the perimeter and area of some shapes.
As for using the formulas, usually you're given all but one of the variables and you can solve for the remaining one.
Notice how the triangle result doesn't have area as a function of a, b and c. That's called Heron's formula and is usually not taught to secondary school students. I don't like to teach it either because Archimedes' Theorem is so much better:
The sides a,b,c and area S of a triangle satisfy

Given:
The boundary line of an inequality is:

The solution set contains (0,0).
To find:
The inequality.
Solution:
The boundary line of an inequality is

Since (0,0) is in the solution set, therefore (0,0) satisfies the required inequality.
Taking LHS, we get

Substitute x=0 and y=0.



The right hand side of the given equation is 6.

We know that,



The boundary line is not a dotted line, it means the points on the boundary line are also included in the solution set. So, the inequality sign must be
.

Therefore, the required inequality is
.