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Masteriza [31]
3 years ago
12

How does a scatter plot show the relationship between paired data?

Mathematics
2 answers:
AysviL [449]3 years ago
6 0
One variable on each axis
lesantik [10]3 years ago
6 0
One variable on each axis
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Using the net below, find the surface area of the triangular prism 5 cm 5 cm 4 cm 4 cm 3 cm 3 cm 3 cm 5 cm​
MatroZZZ [7]

Answer:

54000

Step-by-step explanation:

use multiplication
do ur own work  if you want to see if I'm wrong

7 0
3 years ago
Using a calculator, or otherwise calculate the exact value of 1 4/7 + 2/3 - 1 5/6​
gladu [14]

Answer:

1/6

Step-by-step explanation:

i used a calculator

5 0
3 years ago
Jamal watched his older brother Robert lift weights. The bar alone had a mass of 20 kg. on the bar he had two 11.4 weights, two
Leto [7]
What you have to do is add them all!
   20   bar
11.4   2 11.4 weights
11.4
  4.5   2 4.5 weights
  4.5
450.0   4 450 weights
 450.0
 450.0
+450.0
---------
        1.8
        10
        200
    +1,600
 --------------
     1,811.8 is the answer
6 0
3 years ago
Can a Math expert please solve this and explain their answers. Thanks
Rudik [331]

Answer:

  1. B
  2. 152°
  3. B
  4. A

Step-by-step explanation:

The measure of an arc is twice the measure of the inscribed angle that subtends that arc. A tangent is a special case where the chord that is one leg of the inscribed angle has a length of zero.

1. Short arc LJ is 2a°. Short arc LK is 2b°. Then arc JLK is 2(a+b)°, and short arc JK is ...

  arc JK = 360° -2(a +b)° . . . . . matches choice B

__

2. Long arc WY is twice the measure of "inscribed" angle WYZ, so is ...

  long ard WY = 2(104°) = 208°

Then short arc WY is ...

  arc WXY = 360° -208° = 152°

__

3. The arc measures are double those of the corresponding inscribed angles. We can add up the arcs around the circle:

  (arc AB +arc BC) = 2×70° = 140° . . . inscribed angle relation

  (arc BC +arc CD) = 2×98° = 196° . . . inscribed angle relation

  arc AB + arc BC +arc CD +arc DA = 360° . . . . sum around the circle

Adding the first two equations with arc DA, we have ...

  (arc AB + arc BC) +(arc BC +arc CD) +arc DA = 360° +arc BC

  140° +196° +80° = 360° +arc BC

  416° -360° = arc BC = 56° . . . . . matches choice B

__

4. Angle C and angle A are supplementary in this inscribed quadrilateral.

  angle C = 180° -98° = 82° . . . . . matches choice A

3 0
4 years ago
Suppose you are interested in using regression analysis to estimate a student's GPA using the following independent variables: t
lesantik [10]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
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