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3 years ago

What is the value of x? (7x – 8)° you 62°

Mathematics

1 answer:

Leni [432]3 years ago

4 0

Answer:

x=18

Step-by-step explanation:

180=62+(7x-8)

solve

x=18

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What is the value of y?

enyata [817]

Answer:

y=68

Step-by-step explanation:

Okay, here we go.

180-56=124

124/2=62

62-12=50

62+50=112

180-112=68

y=68

Have a wonderful day!

8 0

3 years ago

A spacecraft is orbiting Mars. At the farthest point in its orbit, it is 76,994 kilometers from Mars. Which of the following num

KengaRu [80]

So scientific notation is
(number>1 and <10) times 10^xpower

so count how many decimal places the decimal needs to move to make 76994 >1 and <10
it needs to move 4 places so
7.6994 times 10^4
the answer is A

5 0

3 years ago

In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini

svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

$x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2$

The augmented matrix is

$\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]$

The reduction of this matrix to row-echelon form is outlined below.

$R_2\rightarrow R_2-R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]$

$R_3\rightarrow R_3-2R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]$

$R_3\rightarrow R_3-R_2$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]$

The last row determines, if there are solutions or not. To be consistent, we must have k such that

$k^2-k-2=0$

$\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2$

Case k = −1:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]$

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]$

This gives the infinite many solution.

5 0

3 years ago

Find the vertex of y=-x^2+6x-12

Debora [2.8K]

You find the x coordinates using x = -b/2a = -6/2(-1) = 3

Substitute 3 in the equation and find y

y = -(3^2) + 6(3) - 12 = -9 + 18 - 12 = -3

Vertex (3,-3)

8 0

3 years ago

Whats the sum of 3/8 and 1/16 a 1/6 b 4/24 c 7/16 d 1/4

Andreyy89

3/8 + 1/16= 7/16
so it's c. 7/16

6 0

3 years ago