Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC= 
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
At least 680 in sales because 200$-64$ is 136. 136*5=680 because 136 is one fifth or 20% of 680
I'm not entirely sure what you mean but simplifying this expression results in 96x + 5 1/2.
Answer:
If Elizabeth randomly chooses her ride in the morning and in the evening, 2/3 is the probability that she'll use a cab exactly one time
You can create and solve a proportion to get this answer.
Let x be the number of litters in 2500.
1. Write out proportion. 1/1000=x/2500
2. Cross Multiply. 1000x=2500
3. Divide by 1000 on each side. x=25
