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3 years ago

5

In a game of tug of war, your team changes -2 1/2 feet in position every 10 seconds. What is your change in position after 40 se

conds? ?This table may help, however there are other ways to solve it. Use whichever method helps you to solve it.

1 answer:

Airida [17]3 years ago

8 0

The answer is -10

-2 1/2 x 4 = -10

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Hello if you could help me that would be great

tankabanditka [31]

2.74x=58.19

x=21.2372

He only has enough lunch money for 21 full days.

3 0

3 years ago

PLEASE HELP ASAP

Svetlanka [38]

Members: 3x + 20
Nonmembers: 5x
$5x = 3x + 20 \\ 5x - 3x = 3x - 3x + 20 \\ 2x = 20 \\ 2x \div 2 = 20 \div 2 \\ x = 10 \: classes$
Hope this helped!!

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3 years ago

Basile [38]

Step-by-step explanation:

<h3>Let the literate and illiterate people of Rashkundu Village be 4x and x respectively then </h3><h3>4x + x = 6550</h3><h3>5x = 6550</h3><h3>x = 6550 / 5</h3><h3>x = 1310</h3><h3 /><h3>Therefore </h3><h3>no. of literate people = 4 * 1310 = 5240</h3><h3 /><h3>no. of illiterate people = 1310 </h3><h3 /><h3>Hope it will help :)</h3>

8 0

3 years ago

Read 2 more answers

HELP ASAP PLEASE & SHOW UR WORK!! THANK YOU <333

alekssr [168]

Answer:

$\bold{x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\quad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7}$

Step-by-step explanation:

$-2x^2-3x+4=0\\\\a=-2\,,\ b=-3\,,\ c=4\\\\\\x=\dfrac{-b-\sqrt{b^2\pm4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(-2)(4)}}{2(-1)}=\dfrac{3\pm\sqrt{9+32}}{-2}\\\\\\x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\qquad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7$

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3 years ago

A 6-pound watermelon costs $2.40 before a 30% discount. Which equation will allow you to find the discounted price of the waterm

V125BC [204]

Answer:

$1.68

Step-by-step explanation:

2.40 x .70 =1.68

8 0

3 years ago

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