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3 years ago

More help :3 please and thnx

Mathematics

1 answer:

Mariana [72]3 years ago

6 0

Answer:

a. there's a lot of options but here are a few: 1 and 5, 5 and 6, 2 and 1, 2 and 6

b. also a lot of options but here are a few: 1 and 6, 5 and 2, 3 and 8, 4 and 7

Step-by-step explanation:

supplementary angles are two angles that add up to 180 degrees, so essentially two angles that, combined, are equal to a straight line.

vertical angles are angles that are opposite each other when two lines cross.

You might be interested in

The snowfall data for Resort A are close to symmetric when they are shown in a box plot. The snowfall data for Resort B are not

ankoles [38]

Answer:

Box and whisker plots are ideal for comparing distributions because the centre, spread and overall range are immediately apparent

Step-by-step explanation:

It is often used in explanatory data analysis

hope this helped

6 0

3 years ago

Read 2 more answers

What is these in simplest form <br> a) 2a + 4 + 5a + 8 = <br> b) -2b – 7 + 3b – 8 =

iren [92.7K]

Answer:

a ) 7a + 12

b) b - 15

Step-by-step explanation:

a)2a+5a +8+8

= 7a + 12

b) b - 7 - 8

= b-15

6 0

3 years ago

Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or

NARA [144]

Answer:

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

Step-by-step explanation:

The function is:

$f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y$

The partial derivatives of the function are included below:

$\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y$

$\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)$

$\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x$

$\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)$

Local minima, local maxima and saddle points are determined by equalizing both partial derivatives to zero.

$y \cdot (8\cdot y -16\cdot x + 9) = 0$

$x \cdot (16\cdot y - 8\cdot x + 9) = 0$

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

$\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.$

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

$x\cdot (-8\cdot x + 9) = 0$

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

$y\cdot (8\cdot y+9) = 0$

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

$H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}$

The second derivatives of the function are:

$\frac{\partial^{2} f}{\partial x^{2}} = 0$

$\frac{\partial^{2} f}{\partial y^{2}} = 0$

$\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9$

Then, the expression is simplified to this and each point is tested:

$H = -16\cdot y +16\cdot x -9$

S1: (0,0)

$H = -9$ (Saddle Point)

S2: (3/8,-3/8)

$H = 3$ (Local maximum or minimum)

S3: (9/8, 0)

$H = 9$ (Local maximum or minimum)

S4: (0, - 9/8)

$H = 9$ (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

$f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64}$ (Local minimum)

S3: (9/8, 0)

$f(\frac{9}{8},0) = 0$ (Local maximum)

S4: (0, - 9/8)

$f(0,-\frac{9}{8} ) = 0$ (Local maximum)

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

4 0

3 years ago

What is the inequality of this graph?

Over [174]

Answer: y < 3x -4

Step-by-step explanation:

We know two points of line: (0,-4) and (1,-1)

Therefore, we can find the slope: 3/1.

We know the y intercept.

Dashed line means the inequality is not apart of the region.

y < 3x-4

7 0

3 years ago

Factor of 2x4+22x3+60x

horsena [70]

Remark

I don't know exactly what level you are in, but the obvious factors are

y = 2x*(x^3 + 11x + 30)

This gives one more factor somewhere around x = -11.3 . Notice that the minimum is around - 3000 or so. I don't think anyone is going to try and take this any further. My calculator figures out cubics and gives an answer of -11.23. There are two other roots but they are a complex pair.

Answer

factor 1: 2x

factor 2: x^3 + 11x^2 + 30

5 0

3 years ago