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Leviafan [203]
2 years ago
10

༒Question༒refer to attachment nonsense will get report​

Mathematics
1 answer:
san4es73 [151]2 years ago
4 0

Answer:

REFER TO ATTACHEMENT

<h2>I HOPE IT IS HELPFUL</h2>

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Given 1 inch = 2.54 centimeters, enter the value that will complete this
vesna_86 [32]
If 1 inch= 2.54 centimeters, 12 inches or 1 foot = 30.48 centimeters, so 3.5 feet = 106.68 centimeters


Mark brainliest please


Hope this helps you
7 0
3 years ago
Find the probability of rolling a 5 or greater on the first die and a 2 or greater on the second die
bekas [8.4K]

Answer:

The probability is 1/9

Step-by-step explanation:

The probability of rolling a 5 the first time is 1/6

The probability of rolling a number greater than 2

Numbers greater than 2 are 3, 4, 5, 6

So the probability of rolling a number out of these four is 4/6

So the probability of rolling a five for the first time and the probability of rolling a number greater than 2 the second time will be

1/6 * 4/6 = 4/36 = 1/9

6 0
3 years ago
Read 2 more answers
Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by
o-na [289]

Answer:

B. \frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

W = \frac{3}{25}

X = \frac{\sqrt{3}}{11}

Y = \frac{9}{100}

Z = \frac{\pi}{24}

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

W = \frac{3}{25}

W = 0.12

X = \frac{\sqrt{3}}{11}

Take square root of 3

X = \frac{1.73205080757}{11}

X = 0.15745916432

X = 0.16 --- approximated

Y = \frac{9}{100}

Y = 0.09

Z = \frac{\pi}{24}

Take π as 3.14

Z = \frac{3.14}{24}

Z = 0.13083333333

Z = 0.13  --- approximated

List out the results, we have:

W = 0.12    X = 0.16    Y = 0.09    Z = 0.13

Order from greatest to least, we have:

X = 0.16     Z = 0.13      W = 0.12       Y = 0.09

Hence, the order of arrangement is:

X = \frac{\sqrt{3}}{11}     Z = \frac{\pi}{24}      W = \frac{3}{25}      Y = \frac{9}{100}

i.e.

\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

6 0
3 years ago
Is there enough information given to find the value of X. Explain your reasoning.
Anna007 [38]
With what you've jus given me, no. is there an equation or something to go along with this question?

4 0
3 years ago
Deer ticks can be carriers of either Lyme disease or human granulocytic ehrlichiosis (HGE). Based on a recent study, suppose tha
san4es73 [151]

Answer:

0.2364

Step-by-step explanation:

We will take

Lyme = L

HGE = H

P(L) = 16% = 0.16

P(H) = 10% = 0.10

P(L ∩ H) = 0.10 x p(L U H)

Using the addition theorem

P(L U H) = p(L) + P(H) - P(L ∩ H)

P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)

P(L U H) = 0.26 - 0.10p(L u H)

We collect like terms

P(L U H) + 0.10P(L U H) = 0.26

This can be rewritten as:

P(L U H)[1 +0.1] = 0.26

Then we have,

1.1p(L U H) = 0.26

We divide through by 1.1

P(L U H) = 0.26/1.1

= 0.2364

Therefore

P(L ∩ H) = 0.10 x 0.2364

The probability of tick also carrying lyme disease

P(L|H) = p(L ∩ H)/P(H)

= 0.1x0.2364/0.1

= 0.2364

3 0
3 years ago
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