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LekaFEV [45]
3 years ago
8

Which is the graph of y=|x|-2?

Mathematics
1 answer:
sergeinik [125]3 years ago
6 0
It looks like a V with the point of the V at the point (0,-2)
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Graph the linear function.<br> 8(x) = x + 3
Nonamiya [84]

Answer:

idk

Step-by-step explanation:

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3 years ago
34. A MasterCard statement shows a balance of $510 at 13.9% compounded monthly. What monthly payment will pay off this debt in 1
bixtya [17]

Answer:

The monthly payment is $35.10.

Step-by-step explanation:

p = 510

r = 13.9/12/100=0.011583

n = 12+4=16

The EMI formula is :

\frac{p\times r\times(1+r)^{n} }{(1+r)^{n}-1 }

Now putting the values in formula we get;

\frac{510\times0.011583\times(1+0.011583)^{16} }{(1+0.011583)^{16}-1 }

=> \frac{510\times0.011583\times(1.011583)^{16} }{(1.011583)^{16}-1 }

= $35.10

Therefore, the monthly payment is $35.10.

8 0
4 years ago
Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21
yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to -4x+7y=21.

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

-4x+7y=21

Slope of this line is

m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

m_1=-\dfrac{-4}{7}

m_1=\dfrac{4}{7}

Product of slope of two perpendicular lines is -1.

m_1\times m_2=-1

\dfrac{4}{7}\times m_2=-1

m_2=-\dfrac{7}{4}

Now, slope of required line is -\dfrac{7}{4} and it passes through (1,-2). So, the equation of line is

y-y_1=m(x-x_1)

where, m is slope.

y-(-2)=-\dfrac{7}{4}(x-1)

4(y+2)=-7(x-1)

4y+8=-7x+7

4y+7x=7-8

7x+4y=-1

Therefore, the equation of required line is 7x+4y=-1.

7 0
3 years ago
HELP ASP Lucy has a jewelry business. To make a certain necklace, she spends $3.38 on materials and $5.57 on labor. She then sel
Nataliya [291]

5.57 + 3.38 =
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3 years ago
What is the value of g(9)?
ryzh [129]
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3 years ago
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