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QveST [7]
2 years ago
13

A 1,800kg rollercoaster is going down a hill with a kinetic energy of 25,000J. What is the velocity of the rollercoaster going d

own the hill?​
Physics
1 answer:
abruzzese [7]2 years ago
5 0

Answer:

K. E = (mv^2)/2

Explanation:

  1. 25000= (1800× v^2)/2
  2. 25000×2= (1800× v^2)
  3. 50000=1800×v^2
  4. 50000/1800= v^2
  5. 27.77777777= V^2
  6. 5.27038=V

Velocity (V) = 5.270 m/sec

Please mark branliest if you are satisfied with the answer. Thanking you in anticipation.

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The forces on one of the wires will be 0.000264 N.It is the field sensed around a moving electric charge that gives rise to the magnetic force.

<h3>What is a magnetic field?</h3>

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.

The given data in the problem is;

I is the current = 6.50 A

B is the magnetic field=f 2.71 X 10⁻⁵ T

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\rm F= BIL \\\\\ F=2.71 \times 10^{-5} \ T \times 6.50 \  A \times 1.50 \ m \\\\\ F=0.000264225 \ N

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