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QveST [7]
2 years ago
13

A 1,800kg rollercoaster is going down a hill with a kinetic energy of 25,000J. What is the velocity of the rollercoaster going d

own the hill?​
Physics
1 answer:
abruzzese [7]2 years ago
5 0

Answer:

K. E = (mv^2)/2

Explanation:

  1. 25000= (1800× v^2)/2
  2. 25000×2= (1800× v^2)
  3. 50000=1800×v^2
  4. 50000/1800= v^2
  5. 27.77777777= V^2
  6. 5.27038=V

Velocity (V) = 5.270 m/sec

Please mark branliest if you are satisfied with the answer. Thanking you in anticipation.

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